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masya89 [10]
3 years ago
9

When the input work on simple machine equals the work the machine is said to be 100% efficient

Physics
1 answer:
Semmy [17]3 years ago
8 0

Answer:

This is not a question, but a statement. The concept that the work done is equal to the input work on a simple machine is called ideal machine. An ideal machine has 100% efficiency which means that there is no loss. All the amount of input work is equal to the useful output of the machine.

Explanation:

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Suppose you are planning a trip in which a spacecraft is to travel at a constant velocity for exactly six months, as measured by
QveST [7]

Answer:

0.999958c

Explanation:

Remember that the trip involves traveling for six months at a constant velocity thus returning home at same speed . The time interval of this trip will therefore be one year.

Accurate time interval to be measured by the clock on the spaceship Δt0 = 1.0 years

Time interval as advanced on earth observed from the spacecraft Δt = 110 years

the formula for time dilation is

Δt = Δt0 /√(1-v2/c2)

or v = c*√1-(Δt0/Δt)2

=c*√[1-(1year/110years)2]

= 0.999958c

3 0
3 years ago
1- an example on a body that it is in motion to an observer and at rest to another.
vesna_86 [32]

Answer:

#1

Explanation:

On a train you are sitting so not in motion but to someone outside the train you are in motion with the train

6 0
3 years ago
In a hydroelectric power plant, water flows from an elevation of 400 ft to a turbine, where electric power is generated. For an
VashaNatasha [74]

Answer:

V=3.475ft^3/s=3.48ft^3/s

Explanation:

We have here values from SI and English Units. I will convert the units to English Units.

We hace for the power P,

P= 100kW \rightarrow 100kW*(\frac{737.56ft.lbf/s}{1kW})

P= 73.7*10^{3}ft.lbf/s

we have other values such h=400ft and  \gamma= 62.42lb/ft^3 (specific weight of the water), and 0.85 for \eta

We need to figure the flow rate of the water (V) out, that is,

V=\frac{P}{\gamma h \eta_0}

Where \eta_0 is the turbine efficiency, at which is,

\eta_0 = \frac{P}{\gamma Vh}

Replacing,

V=\frac{73.7*10^{3}}{62.42*400*0.85}

V=3.475ft^3/s

With this value (the target of this question) we can also calculate the mass flow rate of the waters,

through the density and the flow rate,

m=\rho V\\m= 3.475*1.94 \\m=6.7415 slugs/s

converting the slugs to lbm, 1slug = 32.174lbm, we have that the mass flow rate of the water is,

m= 217lbm/s

6 0
3 years ago
The technique called ____ uses a high-speed computer to monitor atmospheric distortion and adjust the optics of a telescope to p
slavikrds [6]

Answer:

adaptive optics.

Explanation:

Light wave can be defined as an electromagnetic wave that do not require a medium of propagation for it to travel through a vacuum of space where no particles exist.

A lens can be defined as a transparent optical instrument that refracts rays of light to produce a real image.

A telescope can be defined as an optical instrument or device which comprises of a curved mirror and lenses used for viewing distant objects i.e objects that are very far away such as stars and other planetary bodies.

The technique called adaptive optics uses a high-speed computer to monitor atmospheric distortion and adjust the optics of a telescope to partially compensate for the seeing.

Basically, adaptive optics is used by astronomers to correct the distortions caused by the turbulence of the atmospheric conditions of the Earth in real-time, so as to have an image that is as sharp as anyone taken in space.

3 0
3 years ago
What’s the force of a pitching machine on a baseball? Baseballs pitched by a machine have a horizontal velocity of 30 meters/sec
Leya [2.2K]
The acceleration of the baseball is:
a= \frac{v_f-v_i}{\Delta t}
where v_f and v_i are the final and initial speed of the ball, and \Delta t is the time interval in which the force acted.

Replacing the numbers, we get
a= \frac{30 m/s-0m/s}{0.5 s}=60 m/s^2
And at this point, we can use Newton's second law F=ma to find the value of the force of the pitching machine:
F=ma=(0.15 kg)(60 m/s^2)=9 N
5 0
3 years ago
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