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Evgesh-ka [11]
2 years ago
6

A flat sheet is in the shape of a rectangle with sides of lengths 0.400 m and 0.600 m. The sheet is immersed in a uniform electr

ic field of magnitude 95.0 N/C that is directed at 20∘ from the plane of the sheet.
Required:
Find the magnitude of the electric flux through the sheet.
Physics
1 answer:
Katen [24]2 years ago
5 0

Answer:

ФE = 9.403W

Explanation:

In order to calculate the magnitude of the electric flux trough the sheet, you use the following formula:

\Phi_E=\vec{A}\cdot \vec{E}=AEcos\theta       (1)

A: area of the rectangular sheet = (0.400m)(0.600m) = 0.24m^2

E: magnitude of the electric field = 95.0N/C

θ: angle between the direction of the electric field and the normal to the surface of the sheet

You replace the values of the parameters in the equation (1):

\Phi_E=(0.24m^2)(95.0N/m)cos(20\°)=9.304W

The magnitude of the electric flux is trough the sheet is 9.403W

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