Answer:
1)![t=2.26\: s](https://tex.z-dn.net/?f=t%3D2.26%5C%3A%20s)
2)![S=33.9\: m](https://tex.z-dn.net/?f=S%3D33.9%5C%3A%20m)
3)![v=26.77\: m/s](https://tex.z-dn.net/?f=v%3D26.77%5C%3A%20m%2Fs)
4)
Explanation:
1)
We can use the following equation:
![y_{f}=y_{0}+v_{iy}t-0.5*g*t^{2}](https://tex.z-dn.net/?f=y_%7Bf%7D%3Dy_%7B0%7D%2Bv_%7Biy%7Dt-0.5%2Ag%2At%5E%7B2%7D)
Here, the initial velocity in the y-direction is zero, the final y position is zero and the initial y position is 25 m.
![0=25-0.5*9.81*t^{2}](https://tex.z-dn.net/?f=0%3D25-0.5%2A9.81%2At%5E%7B2%7D)
![t=2.26\: s](https://tex.z-dn.net/?f=t%3D2.26%5C%3A%20s)
2)
The equation of the motion in the x-direction is:
![v_{ix}=\frac{S}{t}](https://tex.z-dn.net/?f=v_%7Bix%7D%3D%5Cfrac%7BS%7D%7Bt%7D)
![15=\frac{S}{2.26}](https://tex.z-dn.net/?f=15%3D%5Cfrac%7BS%7D%7B2.26%7D)
![S=33.9\: m](https://tex.z-dn.net/?f=S%3D33.9%5C%3A%20m)
3)
The velocity in the y-direction of the stone will be:
![v_{fy}=v_{iy}-gt](https://tex.z-dn.net/?f=v_%7Bfy%7D%3Dv_%7Biy%7D-gt)
![v_{fy}=0-(9.81*2.26)](https://tex.z-dn.net/?f=v_%7Bfy%7D%3D0-%289.81%2A2.26%29)
![v_{fy}=-22.17\: m/s](https://tex.z-dn.net/?f=v_%7Bfy%7D%3D-22.17%5C%3A%20m%2Fs)
Now, the velocity in the x-direction is 15 m/s then the velocity will be:
![v=26.77\: m/s](https://tex.z-dn.net/?f=v%3D26.77%5C%3A%20m%2Fs)
4)
The angle of this velocity is:
Then α=55.92° negative from the x-direction.
I hope it helps you!
a) we can answer the first part of this by recognizing the player rises 0.76m, reaches the apex of motion, and then falls back to the ground we can ask how
long it takes to fall 0.13 m from rest: dist = 1/2 gt^2 or t=sqrt[2d/g] t=0.175
s this is the time to fall from the top; it would take the same time to travel
upward the final 0.13 m, so the total time spent in the upper 0.15 m is 2x0.175
= 0.35s
b) there are a couple of ways of finding thetime it takes to travel the bottom 0.13m first way: we can use d=1/2gt^2 twice
to solve this problem the time it takes to fall the final 0.13 m is: time it
takes to fall 0.76 m - time it takes to fall 0.63 m t = sqrt[2d/g] = 0.399 s to
fall 0.76 m, and this equation yields it takes 0.359 s to fall 0.63 m, so it
takes 0.04 s to fall the final 0.13 m. The total time spent in the lower 0.13 m
is then twice this, or 0.08s
Answer:
Explanation:
Rx = -28.2 units
Ry = 19.6 units
magnitude of R = √ [( - 28.2 )² + ( 19.6 ) ]
= √ ( 795.24 + 384.16 )
= 34.34 units
If θ be the angle measured counterclockwise from the +x-direction
Tanθ = 19.6 / - 28.2 = -0.695
θ = 180 - 34.8
= 145.2° .
The answer is either C or D.
Answer:
Because a person may be pulled in the direction of the moving train. Thereby causing accident
Explanation:
According to Daniel Bernoulli's theorem, he was widely known as a Mathematician. He stated that due to the higher velocity of a moving train, there is higher kinetic energy in terms of volume around it, while the air pressure between the person and the train becomes lower.
As a result, a person near a moving train may be pulled in the direction of the moving train. Thereby causing accidents that may lead to death.