(8^2)^-4 = 1/8^8
answer
C-1 over 8 times 8 times 8 times 8 times 8 times 8 times 8 times 8
Substitute x with the members of the domain.
f(x) = 5x² + 4
Substitute with the domain of -4
f(x) = 5x² + 4
f(-4) = 5(-4)² + 4
f(-4) = 5(16) + 4
f(-4) = 80 + 4
f(-4) = 84
Substitute with the domain of -2
f(x) = 5x² + 4
f(-2) = 5(-2)² + 4
f(-2) = 5(4) + 4
f(-2) = 20 + 4
f(-2) = 24
Substitute with the domain of 0
f(x) = 5x² + 4
f(0) = 5(0)² + 4
f(0) = 5(0) + 4
f(0) = 0 + 4
f(0) = 4
Substitute with the domain of 1.5
f(x) = 5x² + 4
f(1.5) = 5(1.5)² + 4
f(1.5) = 5(2.25) + 4
f(1.5) = 11.25 + 4
f(1.5) = 15.25
Substitute with the domain of 4
f(x) = 5x² + 4
f(4) = 5(4)² + 4
f(4) = 5(16) + 4
f(4) = 80 + 4
f(4) = 84
The range of the function for those domain is {4, 24, 15.25, 84}
Answer:
(8.97x^2) *(10^80)
Step-by-step explanation:
See attachment
Answer:
n/3 - 18
Step-by-step explanation:
"quotient of a number and 3" is n/3, and so
"18 less than the quotient of a number and 3" as an expression is:
n/3 - 18
Answer:
The answer to your question is below
Step-by-step explanation:
C (-4, 3)
V (-4, 7)
asymptotes = 2 = 
- This is a vertical hyperbola, the equation is
slope = 2
a is the distance from the center to the vertex = 4
b = 2(4) = 8
