Question

WILL GIVE BRAINLIEST

Answer 1

Answer:

(-2, 4)

Step-by-step explanation:

One of the equations is already solved for y, so let's solve the other one for y and by the transitive proprerty of equality, if y = y, then what those y's are equal to are equal to each other.  Solving the first equation for y:

x + y = 2 so

y = -x + 2

Let's fill that in for y in the second equation.  Where

$y=\frac{1}{2}x+5$, making the substitution,

$-x+2=\frac{1}{2}x+5$

Combining like terms and getting the x on one side and the constant on the other side of the equals sign:

$-\frac{3}{2}x=3$

The product of a fraction and its reciprocal is 1 so we will multiply both sides by

$-\frac{2}{3}$ to get:

$(-\frac{2}{3})(-\frac{3}{2})x=(3)(-\frac{2}{3})$

and we end up with x = -2.

Now that we know that, we can sub that in for x in either one of the original equations.  I chose the first one:

If x + y = 2, then -2 + y = 2

and y = 4

Therefore, the solution set is (-2, 4)