Calculate the pOH where [OH⁻]=4.7×10⁻³M:
pOH=-log[OH⁻]
pOH=-log(<span>4.7×10⁻³)
pOH=2.33
Calculate [OH</span>⁻] if the pOH is 1.34:
pOH=-log[OH⁻]
10^(-pOH)=[OH⁻]
[OH⁻]=10^(-pOH)
[OH⁻]=10^(-1.34)
[OH-]=0.0457M or [OH⁻]=4.57×10⁻²M
Calculate pH if the [OH⁻] is 1.74×10⁻²M:
[H⁺]=K(w)/[OH⁻] or pOH=-log[OH⁻]
[H⁺]=(1×10⁻¹⁴)/(1.57×10⁻²) pOH=-log(1.74×10⁻²)
[H⁺]=6.369×10⁻¹³M pOH=1.759
pH=-log[H⁺] pH=14-pOH
pH=-log(6.369×10⁻¹³) pH=14-1.759
pH=12.2 pH=12.2
I hope this helps. Let me know if anything is unclear.
This has to be more specific..........but the name of the cell is called a galvanic cell and cations react at the cathode. Hope this helps.
Molecule C requires the least energy, Molecule B requires more, and Molecule A requires the most.
Explanation:
Molecule C is made up of a triple bond, which requires the most energy to break. Molecule B is made up of a double bond which is not as strong as a triple bond therefore requiring less energy. Molecule A is made up of a single bond which is the least strong thus requiring the least amount of energy.
1. Exothermic, because it’s giving off heat
2. Exothermic, because it’s giving off heat
3. Endothermic, because it’s losing heat
Answer:
Malachite
Explanation:
Malachite is a copper carbonate hydroxide mineral, with the equation Cu2CO3(OH)2. This dark, green-joined mineral solidifies in the monoclinic precious stone framework, and frequently shapes botryoidal, sinewy, or stalagmitic masses, in cracks and profound, underground spaces, where the water table and aqueous liquids give the way to synthetic precipitation. So, the answer is malachite. Best of Luck!