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2 years ago

What is the name of the isotope produced when Californium-251 emits an alpha particle?

Chemistry

1 answer:

Charra [1.4K]2 years ago

3 0

<h3>Answer:</h3>

Curium-247 <em>i.e.</em> ²⁴⁷₉₆Cm

<h3>Explanation:</h3>

Alpha decay is given by following general equation,

ᵃₓA → ⁴₂He + ᵃ⁻⁴ₓ₋₂B

Where;

A = Parent Isotope

B = Daughter Isotope

ᵃ = Mass Number

ₓ = Atomic Number

Californium-251 is the parent isotope in our case and it has 98 protons (atomic number) and is given as,

²⁵¹₉₈Cf

The alpha decay reaction of Californium-251 will be as,

²⁵¹₉₈Cf → ⁴₂He + ²⁴⁷₉₆B

The symbol for B with atomic number 96 was found to be the atom of Curium (Cm) by inspecting periodic table. Hence, the final equation is as follow,

²⁵¹₉₈Cf → ⁴₂He + ²⁴⁷₉₆Cm

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Answer:

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It is given by Bohr's Theory as:

1/λ = Rh (1/n1² - 1/n2²)

where,

λ = wavelength of photon

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n2 = final state = ∞ (since, electron goes far away from atom after ionization)

Rh = Rhydberg's Constant = 1.097 x 10^7 /m

Therefore,

1/λ = (1.097 x 10^7 /m)(1/1² - 1/∞²)

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Now, for energy (E) we know that:

E = hc/λ

where,

h = Plank's Constant = 6.625 x 10^-34 J.s

c = speed of light = 3 x 10^8 m/s

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E = (6.625 x 10^-34 J.s)(3 x 10^8 m/s)/(9.115 x 10^-8 m)

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Answer:

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Explanation:

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Colt1911 [192]

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

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$\%C_E = \frac{E}{T} * 100\%$

Where

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T = Amount of all elements/components

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The amount of oxygen is:

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$E = 2 * 16$

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