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3 years ago

What is a medulla? what do forensic scientists use this for?

Biology

2 answers:

vfiekz [6]3 years ago

5 0

Answer:

medulla is a set of cells that runs through a hair.

Explanation:

The medulla is typically different depending on the species that the hair came from, which makes it one way to distinguish between animal and human hair. Forensic scientists may also look at the shape and color of pigment in the hair and whether or not the hair has been dyed or bleached. As hair grows about one centimeter a month, it may be possible to determine how long it has been since the hair has been dyed or bleached by looking at the natural end of the hair. Forensic scientists also examine hair for any abnormalities or deficiencies that may help them determine whom the hair came from.

Stolb23 [73]3 years ago

4 0

Medulla oblongata is the part of our brain.... hindbrain........this is the center for vomiting.... breathing....etc so maybe scientist do search for any serious hit on that !

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Considering the same population of cats as in Part A, what is the expected frequency of each genotype (TLTL, TLTS, TSTS ) based

zaharov [31]

Answer:

P = f(TLTL) = 0,16

H = f(TLTS) = 0,48

Q = f(TSTS) = 0,36

Explanation:

Hello!

The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values can vary between 0 (absent allele) and 1 (fixed allele).

The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.

In this case, let's say:

f(TL) = p

f(TS) = q

p + q = 1

Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:

TL= 0,4

TS= 0,6

Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.

P = f(TLTL)

H = f(TLTS)

Q = f(TSTS)

Also P + H + Q = 1

And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:

$p^{2} = f(TLTL)$

$2pq = f(TSTL)$

$q^{2} = f(TSTS)$

So, if the population is in balance:

$P = p^{2}$

$H = 2pq$

$Q = q^{2}$

Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:

$f(TLTL) = P = p^{2} = 0,4^{2} = 0,16$

$f(TLTS) = H = 2pq = 2*0,4*0,6 = 0,48$

$f(TSTS) = Q = q^{2} = 0,6^{2} = 0,36$

I hope you have a SUPER day!

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