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Anna35 [415]
3 years ago
5

Jackie runs 1/2 mile in 1/6 hour.how far can she run in one hour?what is here rate of speed?

Mathematics
1 answer:
Murljashka [212]3 years ago
8 0

Simple. one sixth of an hour is 10 minutes. so she can run half a mile in 10 minutes. by doing simple multiplication, you can tell she can run <u>3</u><u> </u><u>miles</u> exact in one hour if she was to keep that pace the whole time. The rate or speed eould be <u>3</u><u> </u><u>miles</u><u> </u><u>per</u><u> </u><u>hour</u><u>,</u> also written as <u>3mph</u><u>.</u>

HOPE THIS HELPED!!! DONT FORGET TO PUT THIS ANSWER AS THE BRAINLIEST

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Answer:

<em>The SUV is running at 70 km/h</em>

Step-by-step explanation:

<u>Speed As Rate Of Change </u>

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

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\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}

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We'll compute  :

d=\sqrt{(0.8)^2+(0.6)^2}=\sqrt{0.64+0.36}

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\displaystyle \frac{x.x'+y.y'}{\sqrt{x^2+y^2}}=20

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x.x'+y.y'=20

Solving for x'

\displaystyle x'=\frac{20-y.y'}{x}

Since y'=-60

\displaystyle x'=\frac{20+0.6(60)}{0.8}

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