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4 years ago

The length of a rectangle is six times its width. If the area of the rectangle is 486 in 2 , find its perimeter.

Mathematics

1 answer:

seraphim [82]4 years ago

5 0

w - width

6w - length

486 in² - area of the rectangle

(w)(6w) = 6w² - area of the rectangle

The equation:

6w² = 486 divide both sides by 6

w² = 81 → w = √81

w = 9 in

l = 6w → l = (6)(9) → l = 54 in

The perimeter: P = 2l + 2w

P = 2(54) + 2(9) = 108 + 18 = 126 in

<h3>Answer: The perimeter is 126in</h3>

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Answer:

The IQR is given by:

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If we want to find any possible outliers we can use the following formulas for the limits:

$Lower= Q_1 - 1.5 IQR$

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And if we find the lower limt we got:

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So then the left boundary for this case would be 3 days

Step-by-step explanation:

For this case we have the following 5 number summary from the data of 144 values:

Minimum: 9 days

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Maximum: 56 days

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$IQR = Q_3 -Q_1 = 28-18= 10$

If we want to find any possible outliers we can use the following formulas for the limits:

$Lower= Q_1 - 1.5 IQR$

$Upper= Q_3 + 1.5 IQR$

And if we find the lower limt we got:

$Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3$

$Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43$

So then the left boundary for this case would be 3 days

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3 years ago

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Answer:

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