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babunello [35]
3 years ago
5

(Apex!) Select the two values of x that are roots of this equation 3x-5=-2x^2

Mathematics
1 answer:
katovenus [111]3 years ago
4 0

Answer:

B and D

Step-by-step explanation:

Write as a quadratic

-2x² - 3x + 5 = 0

Factor

-2x² - 5x + 2x + 5 = 0

-x(2x + 5) + 1(2x + 5) = 0

(1 - x)(2x + 5) = 0

To make the equation 0, x is either 1 or -5/2.

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3 years ago
Solve y – 7 > 3 + 2y A) y -10 D) y > -10
Anika [276]

Answer:

D. -y > 10

Step-by-step explanation:

First, move the variable (+ 2y) to the left-hand side and change its sign.

y - 2y - 7 > 3

Then, move the constant (+ 7) to the right-hand side and change its sign.

y - 2y > 3 + 7

Then, collect the like terms (y - 2y)

-y > 3 + 7

Finally, add the numbers (3 + 7). That will get you your final answer.

-y > 10

7 0
3 years ago
Solve cos 0 = 1 for 0, where 0º = 0 &lt; 90°.<br><br> A) 60°<br> B) 0°<br> C)90<br> D)30
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3 0
2 years ago
What is the solution to the equation One-third (x minus 2) = one-fifth (x + 4) + 2? x = 12 x = 14 x = 16 x = 26
Elena L [17]

Answer:

x = 26

Step-by-step explanation:

Given

\frac{1}{3} (x - 2) = \frac{1}{5} (x + 4) + 2

Multiply through by 15 to clear the fractions

5(x - 2) =3(x + 4) + 30 ← distribute and simplify both sides

5x - 10 = 3x + 12 + 30, that is

5x - 10 = 3x + 42 ( subtract 3x from both sides )

2x - 10 = 42 ( add 10 to both sides )

2x = 52 ( divide both sides by 2 )

x = 26

3 0
3 years ago
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