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3 years ago

Can anyone Help please.

Mathematics

1 answer:

Igoryamba3 years ago

3 0

Answer:

Step-by-step explanation:

The remaining material can be calculated as

volume of larger cube - volume of smaller cube

= a³ - b³ ← difference of cubes which factors in general as

= (a - b)(a² + ab + b²) → D

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Pls help thank you :)

Nastasia [14]

12 m is the area! hope i could help

5 0

3 years ago

Read 2 more answers

What is the value of x in the equation log(x+2) - log(x-1) = log 2

pentagon [3]

Step-by-step explanation:

log(x+2)-log(x-1)=log2

log(x+2)/(x-1)=log2

=> (x+2)=2(x-1)

=>x+2 =2x-2

=> x=4

5 0

3 years ago

It is 280 feet to the cafeteria.how many feet are there in a round trip

kodGreya [7K]

A round trip is twice the distance herein;
So, (280*2) feet
=560 feet

6 0

3 years ago

Use the properties of logarithms to prove log, 1000 = log2 10.

Leto [7]

Given:

Consider the equation is:

$\log_81000=\log_210$

To prove:

$\log_81000=\log_210$ by using the properties of logarithms.

Solution:

We have,

$\log_81000=\log_210$

Taking left hand side (LHS), we get

$LHS=\log_81000$

$LHS=\dfrac{\log 1000}{\log 8}$ $\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]$

$LHS=\dfrac{\log (10)^3}{\log 2^3}$

$LHS=\dfrac{3\log 10}{3\log 2}$ $[\because \log x^n=n\log x]$

$LHS=\dfrac{\log 10}{\log 2}$

$LHS=\log_210$ $\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]$

$LHS=RHS$

Hence proved.

6 0

3 years ago

What is the range of y = sin-1x? [–1, 1] [0, π] left-bracket negative startfraction pi over 2 endfraction, startfraction pi over

soldi70 [24.7K]

The range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].

<h3>What is the range of the function?</h3>

Range of a function is the set of all the possible output values which are valid for that function.

The trigonometry function given in the problem is,

$y = \sin^{-1}x$

The above function can be written as,

$\sin y = x$

The above function is the arc of sine function. The domain of arc of sine ranges from -1 to 1.

$-1\leq x\leq1$

This is the domain of the inverse of sine function. In the attached image below, the graph of inverse sine function is plotted. The range of this function is,

$-\dfrac{\pi}{2}\leq x\leq\dfrac{\pi}{2}$

Thus, the range of the provided inverse sine function in terms of <em>x</em>, and <em>y </em>y = sin-1x is [-π/2, π/2].

Learn more about the range of the function here;

brainly.com/question/2264373

7 0

2 years ago