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3 years ago

-3x+4=13 SOLVE PLZ! INEQUALITY

2 answers:

5 0

Hi!

What you'll first need to do is subtract 4 from 4 and 13. After doing so, your equation will look like this...

-3x=9

Next, you'll need to divide -3x and 9 by -3. After you've done that, you'll get...

x=-3.

So your answer would be x=-3

I hope this helps!

vazorg [7]3 years ago

4 0

-3x+4=13
-4 -4
-3x=13
-3x=9
-x=-3
x=3

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Solve and check.

Aleonysh [2.5K]

Answer:

Step-by-step explanation:

-15.4b + 13 = 9b-41.9

-15.4b-9b = -41.9 - 13

-24.4b= -54.9

divide both side by -24.4

-24.4b/-24.4 = -54.9/-24.4

minus divide by (-)

b= 2.25

3 0

3 years ago

What is the equation of a line that is perpendicular to −x+3y=9 and passes through the point (−3, 2) ?

vekshin1

The equation of line that is perpendicular to the line $-x+3y =9$ and passes through the point $\left({-3,2}\right)$ is $\boxed{{\mathbf{y=-3x-7}}}$ .

Further explanation:

It is given that the equation of line is $-x+3y =9$ and passes through point $\left({-3,2}\right)$ .

Rewrite the given equation $-x+3y =9$ as follows:

$\begin{aligned}-x+3y&=9\\3y&=9+x\\y&=\frac{9}{3}+\frac{1}{3}x\\y&=\frac{1}{3}x+3\\\end{aligned}$

Now, compare the obtained equation of line $y=\frac{1}{3}x+3$ with the standard equation of line $y=mx+b$ .

$\begin{aligned}m&=\frac{1}{3}\\b&=3\\\end{aligned}$

Therefore, the slope is $\frac{1}{3}$ .

It is given that both lines are perpendicular to each other so the product of slope must be equal to $-1$ .

${m_1}\cdot {m_2}=-1$ …… (1)

Substitute $\frac{1}{3}$ for ${m_1}$ in equation (1) to obtain the value of slope ${m_2}$ .

$\begin{aligned}\frac{1}{3}\cdot{m_2}&=-1\\{m_2}&=-3\\\end{aligned}$

Therefore, the slope is $-3$ .

It is given that the line passes through point $\left({-3,2}\right)$ .

The point-slope form of the equation of a line with slope $m$ passes through point $\left({{x_1},{y_1}}\right)$ is represented as follows:

$y-{y_1}=m\left({x-{x_1}}\right)$ …… (2)

Substitute $-3$ for ${x_1}$ , $2$ for ${y_1}$ and $-3$ for $m$ in equation (2) to obtain the equation of line.

$\begin{aligned}y-2&=-3\left({x-\left({-3}\right)}\right)\\y-2&=-3\left({x+3}\right)\\y&=-3x-9+2\\y&=-3x-7\\\end{aligned}$

Therefore, the equation of line is $y=-3x-7$ .

Thus, the equation of line that is perpendicular to the line $-x+3y=9$ and passes through the point $\left({-3,2}\right)$ is $\boxed{{\mathbf{y=-3x-7}}}$ .

Learn more:

1. Which classification best describes the following system of equations? brainly.com/question/9045597

2. What is the value of $x$ in the equation $x-y=30$ when $y=15$ ? brainly.com/question/3965451

3. What are the values of x? brainly.com/question/2093003

Answer Details:

Grade: Junior High School

Subject: Mathematics

Chapter: Coordinate Geometry

Keywords: Coordinate Geometry, linear equation, system of linear equations in two variables, variables, mathematics, equation of line, line, passes through point.

6 0

4 years ago

Read 2 more answers

What are the solutions to the equation? 4x^3=36x

deff fn [24]

I hope this helps you