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3 years ago

Consider two people being randomly selected. (For simplicity, ignore leap years.)

Mathematics

1 answer:

inna [77]3 years ago

7 0

Answer:

$(a) = \frac{144}{133225} \\\\(b) = \frac{1}{365}$

Step-by-step explanation:

Part (a) the probability that two people have a birthday on the 9th of any month.

Neglecting leap year, there are 365 days in a year.

There are 12 possible 9th in months that make a year calendar.

If two people have birthday on 9th; P(1st person) and P(2nd person).

$=\frac{12}{365} X\frac{12}{365} = \frac{144}{133225}$

Part (b) the probability that two people have a birthday on the same day of the same month

P(2 people selected have birthday on the same day of same month) + P(2 people selected not having birthday on same day of same month) = 1

P(2 people selected not having birthday on same day of same month):

$= \frac{365}{365} X \frac{364}{365} =\frac{364}{365}$

P(2 people selected have birthday on the same day of same month) $= 1-\frac{364}{365} \\\\= \frac{1}{365}$

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D(1) = 8 d(n) = d(n-1) x (-5) what is the 3rd term in the sequence

lisov135 [29]

Answer:

With the rule: d(n) = d(n-1) x (-5), we have:

d(1) = 8

d(2) = d(1)x(-5) = 8x(-5) =-40

d(3) =d(2)x(-5) = -40x-5 =200

Other way:

d(n) = d(n-1) x (-5) => d(n) = d(1)x(-5)^(n-1)

d(3) = d(1)x5^(3-1) =8x5^2=8x25 =200

3 0

3 years ago

one box of golfballs costs $112. If you have $7290 and buy as many boxes as you can, how much money will you have left over?

Inessa [10]

Answer:

aproxitmatly 64 to be exact 64.2857

Step-by-step explanation:

Its easy all you have to do is divide 7,200 divided by 112 and eqauls 64

:) Hope you do great on it!

3 0

3 years ago

A trapezoid has base lengths of 5 meters and 3.5 meters. If the height of the trapezoid is 4 meters, what is the area of the tra

aev [14]

Answer:

17 m² or 17 square meters

Step-by-step explanation:

A trapezoid has base lengths of 5 meters and 3.5 meters. If the height of the trapezoid is 4 meters, what is the area of the trapezoid?

Area of a trapezoid =1/2(b1 + b2)h

Where

b1 = First base length = 5m

b2 = Second base length = 3.5 m

Height = 4m

= 1/2(5m + 3.5m) × 4m

= 1/2(8.5m) × 4m

= 1/2 × 8.5m × 4m

= 17 m²

Therefore, the area of the trapezoid is 17 m² or 17 square meters

6 0

3 years ago

Five standard six-sided dice are rolled. We are told there is no three-of-a-kind, but there is a pair of dice that show the same

Neko [114]

The probability that after re-rolling these three dice, at least three of the five dice show the same value is $\frac{4}{9}$

Of the three dice rolled, one may match the original pair and two are different, and this can occur three ways:

$(\frac16 \times \frac56 \times \frac56 ) + ( \frac56 \times \frac16 \times \frac56 ) + ( \frac56 \times \frac 56 \times \frac 16 ) = \frac {75}{216}$

[ where $\frac{1}{6}$ is the probability of matching the first two and $\frac{5}{6}$ is the probability of not matching the first two ]

Or, two may match the original pair and one is different

$( \frac16 \times \frac16 \times \frac 56 ) + ( \frac16 \times \frac56 \times \frac 16 ) + ( \frac56 \times \frac16 \times \frac16 ) = \frac {15}{216}$

Or, all three may match the original pair

$( \frac 16 \times \frac 16 \times \frac 16 ) = \frac {1}{216}$

Or, all three may be the same, but not match the original pair:

$( \frac 56 \times \frac 16 \times\frac 16 ) = \frac {5}{216}$

[ where $\frac{5}{6}$ is the probability of getting a new number and $\frac{1}{6}$ is the probability of matching that new number ]

Adding these together: $\frac {75}{216} + \frac {15}{216} + \frac 1{216} + \frac 5{216} = \frac {96}{216} = \frac 49$

To learn more about probability with the given link

brainly.com/question/11234923

#SPJ4

3 0

2 years ago

Does this graph represent a function? Why or why not?

DedPeter [7]

Answer: C

Step-by-step explanation: For a function, each x-coordinate corresponds to exactly one y-coordinate.

To determine whether the graph shown here

is a function, we can use the vertical line test.

The vertical line test tells us that if each x-coordinate on the graph corresponds to exactly one y-coordinate, then any vertical line that we draw on the graph should hit the graph at only one point.

For the graph show here, any vertical line that you draw with hit the graph at only one point which means it does pass the vertical line test.

So this graph is a <em>function</em>.

8 0

4 years ago