To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
m∠BFE = 171º
BE = 219º
Step-by-step explanation:
∠BFE is supplementary to ∠EFC
m∠BFE = 180 - 9
m∠BFE = 171º
--------------------------
The angle between two chords is equal to half the sum of the intercepted arcs:
∠BFE = (DC + BE)2
171 = (123 + BE)/2
342 = 123 + BE
219º = BE
Step-by-step explanation:
For the triangle on the bottom right the missing angle is
180- (74+50)= 56°
For the triangle on the bottom left the missing angle is
180- (45+80)= 55°
For the triangle in the middle the missing angle is
180- (54+51)= 75°
For the triangle on top the missing angle is
180- (80+54)= 46°
180- (74+51)= 55°
180- (46+55)= 79°
Answer:
y = 14
Step-by-step explanation:
Plug in 4 as x into the equation:
y = 2 + 3x
y = 2 + 3(4)
Simplify:
y = 2 + 12
y = 14
So, when x = 4, y = 14.
The total number of ways the study can be selected is: 637065
Given,
Total number of women in a group= 13
Total number of men in a group = 12
Number of women chosen = 8
Number of men chosen = 8
∴ the total number of ways the study group can be selected = 13C₈ and 12C₈.
This in the form of combination factor = nCr
∴ nCr = n!/(n₋r)! r!
13C₈ = 13!/(13 ₋ 8)! 8!
= 13!/5!.8!
= 1287
12C₈ = 12!/(12₋8)! 8!
= 12!/5! 8!
= 495
Now multiply both the combinations of men and women
= 1287 × 495
= 637065
Hence the total number of ways the study group is selected is 637065
Learn more about "Permutations and Combinations" here-
brainly.com/question/11732255
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