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sattari [20]
3 years ago
8

How do you reduce improper fractions?

Mathematics
2 answers:
tresset_1 [31]3 years ago
8 0
Let me answer this question with an example:

Convert 25/6 into a mixed number.

Let's do it:
25/6
= (24+1)/6
= 24/6 + 1/6
= 4 1/6

That's how you do it. Hope this helps~




11Alexandr11 [23.1K]3 years ago
6 0
You divide the numerator by the denominator
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16. A triangle has side lengths of 6, 8, and 10. Is it a right triangle? Explain. (2 points)
timurjin [86]

Answer:

Yes, because when the side lengths of a triangle are in the ratio 3: 4: 5, then it is a right triangle. These sides are 6: 8: 10, then the triangle is a right one.

Step-by-step explanation:

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3 years ago
What is 2/3+1/2 equal to
Ahat [919]
2/3 + 1/2 is 7/6
Hope this helps!
5 0
3 years ago
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Jennifer has 15 plates and 18 napkins that she wants to arrange in baskets. There needs to be the same number
Paraphin [41]

Answer:

i thik itz 3

Step-by-step explanation:

5 0
3 years ago
A Norman window is a rectangle with a semicircle on top. Suppose that the perimeter of a particular Norman window is to be 24 fe
tekilochka [14]

Answer:

Step-by-step explanation:

Let a is the width of the window and diameter of the semicircle and let h be height of the rectangular portion of the window

:

Perimeter:

2h + a + .5x*pi = 21

2h + 2.57a = 21

2h = 21 - 2.57a

h = (10.5-1.285a)

:

What would be the window with the greatest area;

Area = semicircle + rectangle

Radius = .5a

A = (.5*pi*(.5a)^2) + h*a

Replace h with (10.5-1.285a

A = (1.57*.25a^2) + x(10.5-1.285a)

A = .3927a^2 - 1.285a^2 + 10.5a

A = -.8923a^2 + 10.5a

Find the max area by finding the axis of symmetry; x = -b/(2a)

a = 5.88 meter is the width with the greatest area

:

Find the max area

A = -.8923(5.88^2) + 10.5(5.88)

A = -.8923(5.88^2) + 10.5(5.88)

A = -30.85 + 61.74

A = 30.89 sq/ft is max area

4 0
3 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3


has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
Read 2 more answers
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