Tickets for a play were $2 for each child and $4 for each adult. At one showing of the play, one adult brought 4 children and th

Question

3 years ago

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Tickets for a play were $2 for each child and $4 for each adult. At one showing of the play, one adult brought 4 children and th

e remaining adults brought 2 children each. The total ticket sales from the children and adults are $60. How many CHILDREN attended the play

Mathematics

2 answers:

sertanlavr [38] · Answer 1 · 2021-12-23T19:31:29+03:00

Answer:

16 children attended the play

Step-by-step explanation:

Since one adult brought four children. The cost of their tickets should be:

($4×1) + ($2×1)

= 4+8

= $12

Since the remaining adults brought 2 children each, it means that each of the remaining adults will pay the cost of three tickets (1 for themselves and 2 for their children) which is:

($4×1) + ($2×2) = $4 + $4 = $8.

Since total cost of tickets for adults and children = $60, we will subtract $12 from $60 in order to know the cost of the tickets for the remaining adults and their children.

$60 - $12 = $48

Each of the remaining adults paid $8 as ticket cost for themselves and their kids. If the adults that brought only 2 kids paid a combined $48, then the number of adults that brought 2 kids each

= $48/$8

= 6 adults.

If each of these 6 adults brought 2 kids each, then the number of children that they brought = 2 × 6 = 12

We now add this to the four children of the first adult

12 + 4 = 16

Therefore the number of children that attended the play = 16

oksano4ka [1.4K] · Answer 2 · 2021-12-23T17:49:15+03:00

Answer: 16

Step-by-step explanation:

Tickets for a play were $2 for a child and $4 for an adult.

Tickets price for a child= $2

Tickets price for an adult= $4

One adult brought 4 children. This will give a price of:

(1×4) + (2×4) = 4+8 = $12

The remaining adults brought 2 children each.

Let the remaining adults be y. Each adult will spend:

4+(2×2) = 4+4 = $8

Since there are y adults, it will give 8×y = 8y.

8y + 12 = 60

8y = 60-12

8y = 48

y = 48/8 = 6

The remaining adults are 6. Since we had one adult earlier, total adults will be 7.

To get the number of children that went to the play will be:

(P × number of children) + (price× number of adults) = $60

= (2 × children) + (4 × 7) = $60

= (2 × children) + $28 = $60

= (2 × children) = $60 - $28

= (2 × children) = $32

Children= 32/2

Children= 16

There are 16 children at the play.