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Bas_tet [7]
2 years ago
5

Need help asap please!!!

Mathematics
1 answer:
muminat2 years ago
7 0

Answer:

Bottom Right = (2 x 10^-3) x (4 x 10^4) = 8 x 10^1

Step-by-step explanation:

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The answer to this question is 2.
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Find the area of the triangle. Choices- Question 8 options: a) 70 units2 b) 35 units2 c) 28 units2 d) 14 units2
viva [34]

Answer:

35 (b)

Step-by-step explanation:

Area of a triangle = (height times base)/2

Height = 5

Base = 14

14 times 5 = 70

70/2 = 35

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the point slope form of the equation of the line that passes through (-4 -3) and (12, 1) is y - 1 = 1/4 (x - 12). what is the st
Sergeeva-Olga [200]

Standard Form is ...

ax + by = c

where a ≥ 0, b > 0 (if a=0), and {a, b, c} are mutually prime integers (unless irrational numbers are involved).

You can get there from where you're starting in a couple of steps. Multiply by the least common denominator of any fractions. (Here, you multiply by 4.) Then put the variable terms on the opposite side from the constant term. Make sure the leading coefficient is positive.

... 4y -4 = x -12

... x -4y = 8 . . . . add 12-4y

8 0
3 years ago
This set of ordered pairs shows a relationship between x and y. {(0, -2), (3, 7), (6, 16), (6, 15), (8, 21), (10, 28), (11,31)}
Hunter-Best [27]

Answer:

The closest to the output when the input is approximately 12

Step-by-step explanation:

The given (x, y) coordinates are;

The line of best fit is

x, 0, 3, 6, 6, 8, 10, 11

y, -2, 7, 16, 15, 21, 28, 31

The line of best fit can be obtained from the scatter plot of the given data from where a linear pattern is apparent

A linear line of best fit is a trend line that gives an overall cumulative minimum distance of all the points from the line

The method for constructing a line of best fit includes;

1) The least Squares Method

2) The method of linear regression

3) Construction of line of best fit

a) The area method

b) The dividing method

The least squares equation is given as follows;

\hat y = a + b·x

b = \dfrac{\Sigma (x_i - \overline x) \cdot (y_i - \overline y)}{\Sigma (x_i - \overline x)^2 }

From MS Excel, we have;

{\Sigma (x_i - \overline x) \cdot (y_i - \overline y)}{ } = 266.8571

{\Sigma (x_i - \overline x)^2 } = 89.42857

∴ b = 266.8571/89.42857 ≈ 2.984

a =\overline y- b \cdot \overline x

From MS Excel, with the given data, we get;

\overline y = 16.57143

\overline x = 6.285714

Therefore;

a = 16.57143 - 2.984 × 6.285714 = -2.185

Therefore, we get the following regression equation;

\hat y = -2.185 + 2.9·x

Where;

x = The input

\hat y = The output

Therefore, when x = 5, we get;

\hat y = -2.185 + 2.9 × 5 = 12.315

Therefore, the closest to the output when the input is 5, y ≈ 12

8 0
3 years ago
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