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densk [106]
3 years ago
6

A kite is flying above the ground

Mathematics
2 answers:
andriy [413]3 years ago
8 0

The height of the kite above the ground is 90.63 feet.

<u>Step-by-step explanation:</u>

The angle of elevation of the kite is (θ) 65°.

The distance between the kite and its end is (hypotenuse)100 feet.

To find the height (x) of the kite flying above the ground.

we know that sin(θ) =\frac{height}{hypotenuse}.

sin 65°=\frac{x}{100} .

sin 65° =  0.90631.

0.90631 ×100=x.

90.63=x.

∴The height of the kite above the ground is 90.63 feet.

8_murik_8 [283]3 years ago
3 0

Answer:

109 feet D

Step-by-step explanation:

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Step-by-step explanation:

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And we select a sample size of 64.

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Part a

For this case the mean and standard error for the sample mean would be given by:

\mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

Part b

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

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Part c

For this case we want this probability:

P(\bar X \geq 285)

And we can use the z score defined as:

z=\frac{\bar x -\mu}{\sigma_{\bar x}}

And using this we got:

P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

And using a calculator, excel or the normal standard table we have that:

P(Z\geq2.070)=1-P(Z

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