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snow_tiger [21]
3 years ago
11

Help me plssssss!!!!!!!!

Mathematics
1 answer:
Blizzard [7]3 years ago
4 0

Answer:

ight bet so if 2 and 2 is 4

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2x + 3y = 3 y = 8 – 3x
pentagon [3]
2x + 3y = 3 y = 8 – 3x                     
we have 2 equations

first equations: <span>2x + 3y = 3 y
</span>the second equation: 3y = 8 – 3x => <span>8-3x=3y
</span><span>------------------------------------------------------------
2x+3y=3y</span>2x=3y-3y
2x=0
x=0

8-3x=3y
8-0=3y
8=3y
y=8/3

S={x=0 ; y=8/3 } 

8 0
3 years ago
What is "a" in the question?
Sergeeva-Olga [200]

Answer:

a=2.4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Compute the flux H F of F(x,y) = hxy, x − yi across the boundary of the square given by −1 ≤ x ≤ 1, −1 ≤ y ≤ 1.
Softa [21]

Answer:

4i.

Step-by-step explanation:

To find the flux through the square, we use the divergence theorem for the flux. So Flux of F(x,y) = ∫∫divF(x,y).dA

F(x,y) = hxy,x - yi

div(F(x,y)) = dF(x,y)/dx + dF(x,y)dy = dhxy/dx + d(x - yi)/dy = hy - i

So, ∫∫divF(x,y).dA = ∫∫(hy - i).dA

= ∫∫(hy - i).dxdy

= ∫∫hydxdy - ∫∫idxdy

Since we are integrating along the boundary of the square given by −1 ≤ x ≤ 1, −1 ≤ y ≤ 1, then

∫∫divF(x,y).dA = ∫₋₁¹∫₋₁¹hydxdy - ∫₋₁¹∫₋₁¹idxdy

= h∫₋₁¹{y²/2}¹₋₁dx - i∫₋₁¹[y]₋₁¹dx

= h∫₋₁¹{1²/2 - (-1)/2²}dx - i∫₋₁¹[1 - (-1)]dx

= h∫₋₁¹{1/2 - 1)/2}dx - i∫₋₁¹[1 + 1)]dx

= 0 - i∫₋₁¹2dx

= - 2i[x]₋₁¹

= 2i[1 - (-1)]

= 2i[1 + 1]

= 2i(2)

= 4i  

7 0
3 years ago
Find the slope between the points (-8,-4) and (0,0).
Vadim26 [7]

Answer:

1/2

Step-by-step explanation:

slope = \frac{y_{2}-y_{1} }{x_{2}-x_{1}}

(0-(-4))/(0-(-8)) = 1/2

7 0
2 years ago
Simplify 6 . 3p<br><br> 18p<br><br> 63p<br><br> 18+p<br> 9p
ipn [44]

Answer:

18p

Step-by-step explanation:

6 \times 3p

\boxed{\green{= 18p}}

4 0
2 years ago
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