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kramer
2 years ago
9

Make a table showing all the possible outcomes for spinning the pointer of a spinner with four equal-sized sections labeled 1–4

and another spinner with four equal-sized sections labeled A–D. Use this table to determine the probability that the two pointers will land on an odd number and the letter C. Give the probability as a percent, rounded to the nearest tenth of a percent.
P(odd number, C) =

%
Mathematics
1 answer:
natka813 [3]2 years ago
3 0

Answer:

12.5%

Step-by-step explanation:

There are two types of spinners here and the outcome of them is independent. That means

P(odd number,C) = P(odd number) * P(C)

There are two odd numbers out of four numbers in the first spinner. The chance of odd number will be:

P(odd) = 2/(2+2)= 1/2= 50%

There are four letters and the desired outcome is C. The chance for C will be:

P(C)= 1/4= 25%

Then the chance will be:

P(odd number,C) = P(odd number) * P(C)

P(odd number,C) =50% * 25% = 12.5%

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It looks like it would be C, but I'm not sure 
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4.4 + [4 • 1/4 + 8.6]
Delicious77 [7]

Answer: 4.4 + (4 x 1/4 + 8.6) = 14

Step-by-step explanation: Because starting inside the parenthesis, 4 times 1/4 = 1. Then 8.6 plus 1 = 9.6. Finally, 9.6 plus 4.4 which equals 14. :)

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3 years ago
Bill wanted to know how many times students at his middle school go to the beach each week during the summer. He surveyed every
pshichka [43]

The survey was intended for Bill's middle school during the summer. The

survey was administered to students of other schools on a Saturday.

  • The type of error is the <u>selection bias error</u>.

Reasons:

The type of error made is a non sampling error, given that the target of the

study is the number of times in a week students at his middle school

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The errors are; Selection bias error.

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The selection bias error is a type error that is due to the researcher

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Learn more about selection bias error here:

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2 years ago
A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in
erica [24]

Answer:

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

n=10 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =0.0217 represent the sample variance

\sigma^2_0 =0.12^2= 0.0144 represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 0.0144

Alternative hypothesis: \sigma^2 \neq 0.0144

The statistic can be calculated like this;

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

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Answer:

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Step-by-step explanation:

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