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Setler79 [48]
3 years ago
11

HELP DUE TODAY! Determine if the problem is done correctly AND explain your reasoning. If the problem is correct then explain th

e steps that were taken. If the problem is incorrect then explain what the mistake made was and what the correct solution should be.
1) Multiply the polynomials using the tabular method: (6x2 + 4x – 9)(5x + 1)

Mathematics
2 answers:
Nikolay [14]3 years ago
3 0

Answer:

its correct

Step-by-step explanation:

slava [35]3 years ago
3 0
<h3>The problem was done correctly</h3>

Each term of 6x^2+4x-9 is placed along the top of the table. Each term of 5x+1 is placed along the right side of the table.

We have 3 terms in 6x^2+4x-9 and 2 terms in 5x+1

So there are 3 columns and 2 rows leading to 3*2 = 6 cells total.

Each cell is filled in by multiplying the outer terms

For instance, row 1, column 1 has 6x^2*5x = (6*5)*(x^2*x) = 30x^3

The other cells are filled in the same way.

After the table is completed, you then combine like terms

20x^2 and 6x^2 is one pair which add to 26x^2

4x and -45x is another pair which add to -41x

The other terms are just added on, but not combined/simplified. This leads to the final answer shown on your paper.

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fred ha 227 dollars to spend on 6 books after buying them he had 17 dollars how much did each book cost
NemiM [27]

Answer:

$35

Step-by-step explanation:

If Fred has 227 total and ends up with 17, do 227-17 to determine how much he spent. ($210). If he bought 6 books, then divide $210 by 6.

Hence, each book was $35

7 0
3 years ago
Find the probability that 3 randomly selected people all have the same birthday. ignore leap years. round to eight decimal place
IgorLugansk [536]

Answer:

Probability that 3 randomly selected persons have same birthday = 0.00820417

Step-by-step explanation:

Probability that 1 person has different birthday = 1

\text{Probability that 2nd person has different birthday than 1st = }\frac{364}{365}\\\\\text{Probability that the 3rd person has different from 1st and 2nd = }\frac{363}{365}

\text{Probability that the all three persons have different birthday = }1\times \frac{364}{365}\times \frac{363}{365}\\\\=0.99179583

The probability that all three persons have same birthday = 1 - 0.99179583

                                                                                                 = 0.00820417

Hence, probability that 3 randomly selected persons have same birthday = 0.00820417

7 0
3 years ago
Read 2 more answers
Can anyone help please
harina [27]

The question mark is 5. 8-5=3 and 12-5=7

6 0
4 years ago
Solve this equation! Please Help!<br><br> √3 x 66.15/4.41<br><br> (SHOW YOUR WORK)
finlep [7]
Hi Jessica,
<span>Remember PEMDAS (Parenthesis, Exponents, Multiplication & Division, Addition & Subtraction).

√3 x 66.15/4.41 {Exponents/Cube & Square Roots First}

1.73 x 66.15 ÷ 4.41 {Multiplication}

114.4395 ÷ 4.41 {Division}

25.95 {Final Answer}

Cheers,
Izzy</span>
7 0
3 years ago
Ella's grandmother sewed her a change purse. When she gifted it to her, Ella counted 23 coins already in it. Ella noticed there
juin [17]
The answer to this problem is 17dimes
5 0
3 years ago
Read 2 more answers
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