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3 years ago

15

Find the gcf of 6x^2+18x

1 answer:

svet-max [94.6K]3 years ago

7 0

Ok......

6x^2 + 18x
You would have to find the biggest number that goes into each number that would divide evenly..
6 and 18
The biggest number would be
6
But the x is still in the equation.. so take out one x and you would get
6x
Your greatest common factor

H0P3 It H3LPS :)

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3 years ago

Given: 8x-61=17, prove: 39/4

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The solution is $x = \frac{39}{4}$

Step-by-step explanation:

We are given the following equation:

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3 years ago

the combined age of april and laura is 23 years. laura's age is two years more than half of april's age. what is laura's age

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Laura's age is 9 years.

Solution:

Let x be the age of April.

Laura's age = 2 years more than half of April's age

<u>Convert statement into algebraic expression:</u>

Half of April's age = $\frac{x}{2}$

2 years more than half of April's age = $\frac{x}{2}+2$

Combined age of April and Laura = 23

⇒ April's age + Laura's age = 23

$$\Rightarrow \ \ x+(\frac{x}{2}+2) =23$

$$\Rightarrow \ \ x+\frac{x}{2}+2 =23$

$$\Rightarrow \ \ \frac{x}{1}+\frac{x}{2}+\frac{2}{1} =23$

To add the fractions make the denominators same.

Multiplying 2 on both numerator and denominator of unlike terms, we get

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Denominators are same, now add the fractions.

$$\Rightarrow \ \ \frac{2x+x+4}{2} =23$

Do cross multiplication.

$$\Rightarrow \ \ 2x+x+4=23\times2$

$$\Rightarrow \ \ 3x=46-4$

$$\Rightarrow \ \ 3x=42$

$$\Rightarrow \ \ x=14$

Aprils's age = 14 years

Laura's age = $\frac{14}{2}+2$

= 7 + 2

Laura's age = 9

Hence Laura's age is 9 years.

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