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s344n2d4d5 [400]
3 years ago
11

Graph 3x + 2y = 6. Can someone help with this

Mathematics
2 answers:
Tasya [4]3 years ago
8 0

Here are two ways to graph it.  You can decide which one seems easier to understand or easier to do:

==>  Manipulate the equation into the "slope-intercept" form, where 'y' is
all alone on one side and everything else is on the other side:

3x + 2y = 6

Subtract  3x  from each side:   2y = -3x + 6

Divide each side by  2 :            y = <em>-3/2</em> x <em>+</em> <em>3</em>

This is the form you want.  Just looking at it, it tells you that the slope
of the line on the graph is (<em>-3/2</em>), and it crosses the y-axis at  <em>+3</em> .
That's enough information to draw the line.
===============================================

=>  Another way:

Look at the x-axis and the y-axis on the graph paper ... without any graph drawn on it yet.  Just look at the 2 axes.

With an 'x'-number and a 'y'-number, you can find any point on it. Right ?

OK.  Notice that at every point on the y-axis, x = 0 .  And at every point
on the x-axis, y = 0.  This can be very very helpful.

Now take your equation:    <u>3x + 2y = 6 .</u>

You know that the graph is going to be a straight line.  And it's pretty obvious that if the line isn't horizontal or vertical, then it has to cross both the x-axis and the y-axis somewhere.  If you had an easy way to find the two points where it crosses the axes, you could join those 2 points and you'd have your line !

You DO have an easy way to find those points !

If x=0, then the point is on the y-axis.  Take your equation, make x=0, and it'll show you where the line crosses the y-axis:

                         3(0) + 2y = 6 .

                                    2y = 6 .

Divide each side by 2 :  y = 3 .

There's one point on the line:  (0, 3)

Now remember that if y=0 the point is on the x-axis.  So take your equation
and make y=0:

                                      3x + 2(0) = 6

                                      3x          = 6

Divide each side by 3 :    x = 2 

There's another point on the line, where it crosses the x-axis:  (2, 0) .

Shazam !  You have the 2 points where the line crosses the x- and
y- axes.  Mark each one with a little dot,  put your ruler down along
them, draw a line between them, and extend it as far in each direction
as you want to.  That's the graph of your equation.


WARRIOR [948]3 years ago
3 0
Plot these coordinates then draw a line through them and that is the line.

(2,0) x intercept
(0,3) y intercept
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Please help me. math.
KiRa [710]

Answer:

y =293(1.06) ^x

y = 370  after 4 years

Step-by-step explanation:

If we are using the model for growth

y = a ( 1+b)^x

a is the initial population

b is  the increase rate

We can substitute the values into the equation

y =293 (1+.06) ^ x

y =293(1.06) ^x


Let x equal 4 for the 4 years

y = 293(1.06)^4

y=369.9



3 0
3 years ago
-4x-3(-44-23)=13<br><br><br> please show the work, i’ll mark brainliest
pychu [463]

Answer:

47

Step-by-step explanation:

Let's solve your equation step-by-step.

−4x−3(−44−23)=13

Step 1: Simplify both sides of the equation.

−4x+201=13

Step 2: Subtract 201 from both sides.

−4x+201−201=13−201

−4x=−188

Step 3: Divide both sides by -4.

−4x

−4

=

−188

−4

x=47

3 0
2 years ago
4/5 + 1/3 <br><br> Answers should be in format example: 5/2 or 2/5. No decimals or mixed numbers.
spin [16.1K]

Answer:

16/15

Step-by-step explanation:

The LCM of 5 and 3 is 15

4/5 + 1/3 = 12 / 15 + 4 / 15 = 16 / 15

3 0
3 years ago
Read 2 more answers
11. GARDEN Emily calculates that the area of a flower garden is 28.125. She measured
Svetlanka [38]

Answer:

A=28.13 Sq Ft

Step-by-step explanation:

Given that the length of the garden = 4.5 ft

Breadth of the garden = 6.25 ft

Area is given by the formula

A=length x breadth

A=4.5 x 6.25 sq ft

A= 28.125 sq ft

Here if we round the area to the nearest hundredth, the area will be

A=28.13 Sq Ft

7 0
3 years ago
Please help 50 points!<br> Simplify the expressed
LenKa [72]

Answer:

Step-by-step explanation:

\frac{x^{2} -x-12}{x+4} * \frac{2x^{2}-32 }{x^{2} -8x+16}  rewrite as multiplication

\frac{x^{2} +3x-4x-12}{x+4} * \frac{2(x^{2}-16) }{x^{2} -8x+16}  look to factor

\frac{x(x+3)-4(x+3)}{x+4} * \frac{2(x-4)(x+4) }{(x-4)^{2}}  , difference of 2 squares and perfect square

\frac{(x+3)(x-4)}{x+4} * \frac{2(x-4)(x+4) }{(x-4)^{2}}, finish factoring and simplify

2(x+3)

3 0
2 years ago
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