Three cities form a right triangle on a map. Cities B and C are the furthest apart. If cities A and B are 14 miles apart And cit
ies A and C are 22 miles apart how far are cities B and C?
1 answer:
Answer:
26.1miles
Step-by-step explanation:
If three cities A, B and C form a right triangle on a map, and the Cities B and C are the furthest apart, then the distance between cities B and C will be the hypotenuse of the triangle.
If cities A and B are 14 miles apart, then |AB| = 14miles
Also if cities A and C are 22 miles apart, then |AC| = 22miles.
To get |BC| which is the distance between cities B and C, we will use the Pythagoras theorem.
|BC|² = |AB|² + |AC|²
|BC|² = 14²+22²
|BC|² = 196+484
|BC|² = 680
|BC| = √680
|BC| = 26.1miles
This means that cities B and C are 26.1miles apart
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