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shusha [124]
3 years ago
5

I need help with my math A.S.A.P.

Mathematics
1 answer:
harina [27]3 years ago
3 0
What you have to do it 12*15*3.14=
and you take that answer and divide it by 20.14 
You might be interested in
Does x equal if the problem is negative x -4x - 7 equals 5 negative 2X
Sphinxa [80]

Answer:

X = - 4

Step-by-step explanation:

Given in problem

- x -4x - 7 = 5 -2x

Or, -5x - 7 = 5- 2x

Or, -5x + 2x = 5 + 7

Or, -3x = 12

Or, x = - \frac{12}{3}

∴ X = - 4    Answer

6 0
3 years ago
Multiply.
Kamila [148]
Expand the following:
(x - 6) (3 x^2 + 10 x - 1)
Hint: | Multiply out (x - 6) (3 x^2 + 10 x - 1).
 | | | | x | - | 6
 | | 3 x^2 | + | 10 x | - | 1
 | | | | -x | + | 6
 | | 10 x^2 | - | 60 x | + | 0
3 x^3 | - | 18 x^2 | + | 0 x | + | 0
3 x^3 | - | 8 x^2 | - | 61 x | + | 6:
Answer:  3 x^3 - 8 x^2 - 61 x + 6 Thus B:
7 0
3 years ago
What angle are these?
Grace [21]

Answer:

Corresponding Angles and Alternate Exterior

Step-by-step explanation:

The angles are corresponding if same side in a parallel.

This is because as the lines are parallel to one another that means that the next following angle measure is the same in approach.

For the other problems if they are opposite sides from one another.

They are called alternate exteriors.

5 0
2 years ago
Find dy/dx if f(x) = (x + 8)^3x.
vlabodo [156]
This is quite a complex problem. I wrote out a really nice solution but I can't work out how to put it on the website as the app is very poorly made. Still, I'll just have to type it all in...

Okay so you need to use a technique called logarithmic differentiation. It seems quite unnatural to start with but the result is very impressive.

Let y = (x+8)^(3x)

Take the natural log of both sides:

ln(y) = ln((x+8)^(3x))

By laws of logarithms, this can be rearranged:

ln(y) = 3xln(x+8)

Next, differentiate both sides. By implicit differentiation:

d/dx(ln(y)) = 1/y dy/dx

The right hand side is harder to differentiate. Using the substitution u = 3x and v = ln(x+8):

d/dx(3xln(x+8)) = d/dx(uv)

du/dx = 3

Finding dv/dx is harder, and involves the chain rule. Let a = x+ 8:

v = ln(a)
da/dx = 1
dv/da = 1/a

By chain rule:

dv/dx = dv/da * da/dx = 1/a = 1/(x+8)

Finally, use the product rule:

d/dx(uv) = u * dv/dx + v * du/dx = 3x/(x+8) + 3ln(x+8)

This overall produces the equation:

1/y * dy/dx = 3x/(x+8) + 3ln(x+8)

We want to solve for dy/dx, achievable by multiplying both sides by y:

dy/dx = y(3x/(x+8) + 3ln(x+8))

Since we know y = (x+8)^(3x):

dy/dx = ((x+8)^(3x))(3x/(x+8) + 3ln(x+8))

Neatening this up a bit, we factorise out 3/(x+8):

dy/dx = (3(x+8)^(3x-1))(x + (x+8)ln(x+8))

Well wasn't that a marathon? It's a nightmare typing that in, I hope you can follow all the steps.

I hope this helped you :)
8 0
4 years ago
What would be the steps to solving this problem?<br><br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D" id="TexFormula
lidiya [134]
Isolate the variable by dividing each side by factors that don’t contain the variable.

X = -2

Hope this helps!
Have a great day!
3 0
2 years ago
Read 2 more answers
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