Okay. Basically, a is greater than or equal to 9.
First, you do distribute the 2.
8a+2-10a(< or =)20
Subtract two on both sides.
8a-10a(< or =)18
Then subtract 10a from 8a
-2a(< or =)18
Divide by two on both sides
and switch around the greater than sign since you divided by a <span>-2
</span>a(> or =)-9
<span>And if you check, -9 works, -8 works, and -10 doesn't work.</span>
Answer:
1. Technically 2, but might be 0 in your teacher's opinion.
2. 1
Step-by-step explanation:
Solving problem one.
So I don't know if you have learned about imaginary numbers, but if you have, then you would end up with two answers if you plugged in the quadratic formula.
If you haven't learned about imaginary numbers, then I would say your best option would be to write 'No real solution' since there are technically 2 solutions.
Solving problem two.
Turns out this quadratic has a special property and it's actually a square of one equation. You can find out by just factoring the equation.
It's (3x-2)^2. Since it's squared, that means that only 2/3 would work as x in this equation.
Answer: function 1
Rate of change of function 1:
Following the format of y=mx+c, the rate of change should be m, so, the rate of change for function 1 = 4
To find the gradient (rate of change):
The two points the line passes through are (x1, y1) and (x2, y2), which in this case is (1, 6) and (3, 10)
(Doesn't matter which is which but you need to make sure that once you decide which is which, you stick to it)
To calculate the gradient, you substitute these values following (y1 - y2)/(x1 - x2)
Gradient of function 2 = (10 - 6)/(3 - 1)
= 2
Therefore, since 4 > 2, rate of change of function 1 > rate of change of function 2.
Answer:
what are u trying to say explain more please
Answer:
G^Y boyyyy
Step-by-step explanation:
no because the answer will not apear until you pay attention in class bum
