Answer:
The 99% confidence interval for the true mean number of Banana Bombs in 10.40 ounce packages is between 689.3 and 703.86.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
That is z with a pvalue of 
, so Z = 2.575.
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 696.58 - 7.28 = 689.3 pieces
The upper end of the interval is the sample mean added to M. So it is 696.58 + 7.28 = 703.86 pieces
The 99% confidence interval for the true mean number of Banana Bombs in 10.40 ounce packages is between 689.3 and 703.86.
Answer:
108
Step-by-step explanation:
Limit as x approaches 9 of x^2 -81/sqrt of x - 3
First substitute x into the expression
= 9²-81/√9 - 3
= 81-81/3-3
= 0/0 (indeterminate)
Apply l'hospital rule
= lim x -> 9 d/dx(x²-81)/√x - 3
= lim x -> 9 2x/1/2√x
Substitute x = 9
= 2(9)/1/2√9
=18/1/(2(3)
=18 × 6/1
= 108
Hence the limit of the function is 108
Answer:
The sample of 15 pieces of colored fruit snacks
Step-by-step explanation:
The sample of 15 pieces of colored fruit snacks. The 60 pieces are from ONE day which means it can be heavily biased. It might be like "BLUE RASPBERRY SPECIAL DAY!" or "PRESIDENTS DAY!! RED BLUE AND WHITE!!". However, 15 pieces, whilst having less of a population, is probably more spaced out.
Answer:
D. 64 oz.
Step-by-step explanation:
There are 16 ounces in a pound. So multiply 4 x 16 to get 64 ounces.
Hope it helps!
