Answer:
X = 3°
Step-by-step explanation:
Since O and T are parallel you can use alternating lines
7x + 5° = 5x + 11° (alt. angles, O||T)
Move the 5x and the 5°
7x - 5x = 11° - 5°
2x = 6°
Divide both sides by 2
x = 3°
This is assuming 11 is an angle
50 since a triangle has to equal 180, trust!
Sq of 196 is 14 then x2 = 28 then 25= 5
Answer:Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:
y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5
To try to discard one of them, let us use the vertex, which is at x = -2.
With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.
Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.
Step-by-step explanation:
