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3 years ago

An atom has 5 protons and 7 neutrons. What is its mass number of amu?

Chemistry

1 answer:

xz_007 [3.2K]3 years ago

4 0

You add the protons and neutrons together, so the mass = 12

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1.25 is the closest to 1.04 or not I want to answer please. I think it's true, but I want to prove it scientifically, please.

PSYCHO15rus [73]

Answer:

false because if you round both of them

3 0

3 years ago

Hey guys so my cuz gave me this stone when he went to mexico

Viktor [21]

Looks like candy lol .....

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3 years ago

5.25 calories are absorbed by an iron nail. How many joules is this?

aniked [119]

Answer:

D) 21.9

Explanation:

1 kilocalorie is equal to 4184 joules

0.001 kilocalorie is equal to 1 calorie

so 5.25 calorie=21.966 joules

7 0

4 years ago

Calculate the molarity of a solution consisting of 65.5 g of K2S0 4 in 5.00 L of solution.

tia_tia [17]

Answer:

Molarity is 0.075 M. 

Explanation:

Moles:

${ \tt{ = \frac{65.5}{RFM} }}$

RFM of potassium sulphate :

${ \tt{ = (39 \times 2) + 32 + (16 \times 4)}} \\ = 174 \: g$

substitute:

${ \tt{moles = \frac{65.5}{174} = 0.376 \: moles}}$

In volume of 5.00 l:

${ \tt{5.00 \: l = 0.376 \: moles}} \\ { \tt{1 \: l = ( \frac{0.376}{5.00} ) \: moles}} \\ { \tt{molarity = 0.075 \: mol \: l {}^{ - 1} }}$

8 0

3 years ago

An incompressible Newtonian fluid is brought to flow in a pipe by pulling a wire in the center at a velocity of 18 cm/s. The wir

weqwewe [10]

Answer:

The shear stress is 2.16 Pa

Explanation:

Newton's law of viscosity can be expressed as follows;

$\tau =\mu \times \dfrac{dv}{dy}$

Where:

τ = Shear stress in the fluid

Given that the diameter of the wire = 5 cm

The velocity of the wire = 18 cm/s

The diameter of the pipe = 10 cm

The fluid viscosity, μ = 3.0 cp = 1×10⁻³· Pa·s

The change in velocity from the surface of the wire to the internal surface of the pipe = dv = 18 cm/s

The change in the y (perpendicular) direction of motion of the fluid from the surface of the wire to the interior surface of the tube = dy = 10/2 - 5/2 = 2.5 cm

By putting in the values, we have;

$\tau =0.3 \times \dfrac{18}{2.5} = 2.16 \ Pa$

The shear stress = 2.16 Pa

7 0

3 years ago