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Svetradugi [14.3K]
3 years ago
15

15. A pipe leaks water at a rate of 1.24 mL/s. What is the rate of the water leak in L/hr? ALL

Chemistry
1 answer:
alex41 [277]3 years ago
8 0

Answer:

4.46

Explanation:

1.24 ml= 0.00124 L

3600 s=1 hr

0.00124 x 3600=4.46

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What is an atom? A- the smallest particle of an element. B- the negatively charged particle found in a cloud. C- the densely pac
cestrela7 [59]

Answer:

A

Explanation:

it is the most basic unit of matter

5 0
3 years ago
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A breakfast of cereal, orange juice, and milk might contain 230 nutritional Calories. How much is this in Joules?
Sophie [7]

Answer:

B

Explanation:

962,320 J

230 nutritional Calories in Joules is 962,320 J

4 0
2 years ago
Mixtures of benzene and cyclohexane exhibit ideal behavior. A solution was created containing 1.5 moles of liquid benzene and 2.
goblinko [34]

Answer:

Vapour pressure of cyclohexane at 50°C is 490torr

Vapour pressure of benzene at 50°C is 90torr

Explanation:

Using Raoult's law, pressure of a solution is defined by the sum of the product sbetween mole fraction of both solvents and pressure of pure solvents.

P_{solution} = X_{A}P^0_{A}+X_{B}P^0_{B}

In the first solution:

X_{cyclohexane}=\frac{2.5mol}{2.5mol+1.5mol} =0.625

X_{benzene}=\frac{1.5mol}{2.5mol+1.5mol} =0.375

340torr = 0.625P^0_{A}+0.375P^0_{B} <em>(1)</em>

For the second equation:

X_{cyclohexane}=\frac{3.5mol}{3.5mol+1.5mol} =0.700

X_{benzene}=\frac{1.5mol}{3.5mol+1.5mol} =0.300

370torr = 0.700P^0_{A}+0.300P^0_{B}<em>(2)</em>

Replacing (2) in (1):

340torr = 0.625P^0_{A}+0.375(1233.3-2.333P^0_{A})

340torr = 0.625P^0_{A}+462.5-0.875P^0_{A}

-122.5torr = -0.250P°A

P^0_{A} = 490 torr

<em>Vapour pressure of cyclohexane at 50°C is 490torr</em>

And for benzene:

370torr = 0.700*490torr+0.300P^0_{B}

P^0_{B}=90torr

<em>Vapour pressure of benzene at 50°C is 90torr</em>

3 0
3 years ago
(5.625 + 8.15) x 2.34 + 3.2
dalvyx [7]

The answer is 35.4335

Hope this helped! (Plz mark me brainliest!)

3 0
3 years ago
Read 2 more answers
A gas under an initial pressure of 0.60 atm is compressed at constant temperature from 27 L to 3.0 L. The final pressure becomes
IRINA_888 [86]

Answer: 5.4

Explanation:

P2 = P1V1/V2

P2 = (.60atm x 27L) / 3.0L  = 5.4atm

8 0
3 years ago
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