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Furkat [3]
3 years ago
5

Frank averages one strike for every six frames that he bowls. If he bowled 76 strikes in one season, how many frames did Frank b

owl? A. 190 frames B. 450 frames C. 456 frames D. 228 frames
Mathematics
2 answers:
lora16 [44]3 years ago
7 0
76*6=456 frames in one season (C)
raketka [301]3 years ago
5 0
I think the answer is C. because you would multiply 76 by 6 to get the answer C.

 
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Solve 4x2-25&lt;0<br><br> in words 4x squared -minus 25 &lt; 0
muminat
<h3>I'll teach you how to solve 4x^2-25<0</h3>

-------------------------------------------------

4x^2-25<0

Add 25 to both sides:

4x^2-25+25 < 0+25

Simplify:

4x^2 < 25

Divide both sides by 4:

4x^2/4 < 25/4

Simplify:

x^2 < 25/4

whole sqrt -25/4 < x < whole sqrt 25/4

whole sqrt 25/4= 5/2

-5/2 < x < 5/2

Your Answer Is -5/2 < x < 5/2

plz mark me as brainliest if this helped :)

4 0
3 years ago
A dish has 212 bacteria in it. The population of the bacteria will grow ata rate of 80% every 2 days. How many bacteria will be
mr_godi [17]
If they are growing 80% for every twodays, it would be 40% for every one day.

Bacteria after 9 days = 212 * 9 * 40 / 100
= 763.2
To round up, the population of bacteria after 9 days would be 763, with a growth rate of 80% for every two days.
6 0
2 years ago
10. There are 355 students at Median Middle School. If there 8% of the students were absent on Tuesday, how many students were a
Setler79 [48]

To solve this question, we simply need to divide the total amount of students by 8% to find out how many students were absent and how many were present.

However, we can't simply multiply it by 8%, so we need to turn that into a decimal.

8% - 0.08

<em>Multiply:</em>

<em>355 x 0.08</em>

<em>= 28.4</em>

<em>Round:</em>

<em>28 kids were absent</em>

<em>Subtract:</em>

<em>355 - 28</em>

<em>= 327</em>

<em />

<em>This means that </em><em>28 kids were absent</em><em>, and </em><em>327 kids were present</em><em>.</em><em> </em>

<em />

<em />

6 0
1 year ago
If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),
Marrrta [24]

Answer:

a = 3

b = 2

c = 0

d = -4

Step-by-step explanation:

Form 4 equations and solve simultaneously

28 = a(2)³ + b(2)² + c(2) + d

28 = 8a + 4b + 2c + d (1)

-5 = -a + b - c + d (2)

220 = 64a + 16b + 4c + d (3)

-20 = -8a + 4b - 2c + d (4)

(1) + (4)

28 = 8a + 4b + 2c + d

-20 = -8a + 4b - 2c + d

8 = 8b + 2d

d = 4 - 4b

Equation (2)

c = -a + b + d + 5

c = -a + b + 4 - 4b+ 5

c = -a - 3b + 9

28 = 8a + 4b + 2c + d (1)

28 = 8a + 4b + 2(-a - 3b + 9) + 4 - 4b

28 = 6a - 6b + 22

6a - 6b = 6

a - b = 1

a = b + 1

220 = 64a + 16b + 4c + d (3)

220 = 64(b + 1) + 16b + 4(-b - 1 - 3b + 9) + 4 - 4b

220 = 60b + 100

60b = 120

b = 2

a = 2 + 1

a = 3

c = -3 - 3(2) + 9

c = 0

d = 4 - 4(2)

d = -4

8 0
3 years ago
Read 2 more answers
Solve for x does anyone know how to do this?​
riadik2000 [5.3K]

Answer:

x = 9

Step-by-step explanation:

The sum of the 4 angles in a quadrilateral = 360°

Sum the given angles and equate to 360

90 + 109 + 9x - 5 + 85 = 360, that is

9x + 279 = 360 ( subtract 279 from both sides )

9x = 81 ( divide both sides by 9 )

x = 9

6 0
3 years ago
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