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Serhud [2]
3 years ago
13

A sensor is used to monitor the performance of a nuclear reactor. The sensor accu-rately reflects the state of the reactor with

a probability of .97. But with a probabilityof .02, it gives a false alarm (by reporting excessive radiation even though the reac-tor is performing normally), and with a probability of .01, it misses excessive radia-tion (by failing to report excessive radiation even though the reactor is performing abnormally). (a) What is the probability that a sensor will give an incorrect report, that is, either a false alarm or a miss?
Physics
1 answer:
Helen [10]3 years ago
7 0

Answer:

The probability of an incorrect report is found to be 0.03 or 3%.

Explanation:

We will get an incorrect report in both the cases of false alarm or missing excessive radiation. Since, both are mutually exclusive events. Therefore, the probability of both events to occur simultaneously will be 0. Thus, the probability of an incorrect report will be the sum of the probability of false alarm and the probability of a missing radiation.

P (False Alarm) = 0.02

P (Missing Radiation) = 0.01

P(Incorrect Report) = P (False Alarm) + P(Missing Radiation)

P (Incorrect Report) = 0.02 +0.01

P(Incorrect Report) = 0.03 = 3%

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Two wooden crates rest on top of one another. The smaller top crate has a mass of m1 = 25 kg and the larger bottom crate has a m
faust18 [17]

Answer:

Explanation:

Let the bigger crate be in touch with the ground which is friction less. In the first case both m₁ and m₂ will move with common acceleration because m₁ is not sliding over m₂.

1 ) Common acceleration a = force / total mass

= 234 / ( 25 +91 )

= 2.017 m s⁻².

2 ) Force on m₁ accelerating it , which is nothing but friction force on it by m₂

= mass x acceleration

= 25 x 2.017

= 50.425 N

The same force will be applied by m₁ on m₂ as friction force which will act in opposite direction.

3 ) Maximum friction force that is possible between m₁ and m₂

= μ_s m₁g

= .79 x 25 x 9.8

= 193.55 N

Acceleration of m₁

= 193 .55 / 25

= 7.742 m s⁻²

This is the common acceleration in case of maximum tension required

So tension in rope

= ( 25 +91 ) x 7.742

= 898 N

4 ) In case of upper crate sliding on m₂ , maximum friction force on m₁

=  μ_k m₁g

= .62 x 25 x 9.8

= 151.9 N

Acceleration of m₁

= 151.9 / 25

= 6.076 m s⁻².

6 0
2 years ago
“All dogs bark. Fido barks. Thus, Fido is a dog,” is an example of which of the following?
nalin [4]
Deductive reasoning?
4 0
3 years ago
Two trucks are traveling in the same direction, one going twice as fast as the other. at the end of 6 hours they are 204 miles a
Gemiola [76]
<span>speed of slower=x; distance in 6 hours is 6x
 speed of larger=2x; distance in 6 hours is 12x
 12x-6x=204 miles
</span><span> 6x=204
 x=34 mph slower, 204 miles in 6 hours.
 2x=68 mph, faster, 408 miles in 6 hours, and difference is 204 miles</span>
6 0
3 years ago
Read 2 more answers
What is the equivalent resistance of a circuit that contains four 75.02
viktelen [127]

Answer:

option A is the correct answer

3 0
2 years ago
WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!
faust18 [17]

Answer:

9)a

10) I think true

11)b

Explanation:

9)a. because it's told that the car is slowing down, the sum of the forces that are towards left, should be more than the ones that are towards right. if the car was gaining speed, "b" would have been correct. and if it was told that the car is moving without a change in the speed, "c" would have been correct.

10) if a moving object has a change of speed or direction, it would have an acceleration. now if a moving object experiences an unbalanced force, it'd either slow down, gain speed or change direction, and in all of the three possibilities it'd have an acceleration.

11) upward and downward forces are equal, and the sum of them would be 0N(because they have opposite directions). so they negate each other.

and the rightward force is 5N more than the leftward force. so the Net Force would be 5N.

-30+30-10+15=5N

if it is unclear or you need more explanation, ask freely.

8 0
3 years ago
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