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Vesna [10]
4 years ago
14

A 5.00-a current runs through a 12-gauge copper wire (diameter 2.05 mm) and through a light bulb. copper has 8.5 * 1028 free ele

ctrons per cubic meter. (a) how many electrons pass through the light bulb each second
Physics
2 answers:
Sholpan [36]4 years ago
8 0

Answer:

\frac{dN}{dt} = 3.125 \times 10^{19} electrons per second

Explanation:

As we know that electric current is defined as rate of flow of electric charge

so here we will have

i = \frac{dq}{dt}

here we know that

q = Ne

now from above equation

i = e\frac{dN}{dt}

here we know

\frac{dN}{dt} = number of electrons passing per second

e = charge of an electron

i = 5.00 Ampere

now from above equation we have

\frac{dN}{dt} = \frac{i}{e}

\frac{dN}{dt} = \frac{5}{1.6 \times 10^{-19}}

\frac{dN}{dt} = 3.125 \times 10^{19}

so above is the total number of electrons passing through wire per second

vlada-n [284]4 years ago
7 0

The correct answer is: 3.125*10^{19} electrons/second

Explanation:

5A current is passing through the copper wire and the light bulb; it means that 5 Coulombs of charge per second is passing through the wire (as current = coulombs/second). To find the electrons per second, the following formula is used:

Electrons per second = n_e=\frac{5}{e}=\frac{5}{ 1.60\cdot 10^{-19}}=3.125*10^{19}

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Answer:

Explanation:

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T² = 4 π² R³ / GM

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Substituting the values in the equation

(.3189 x 24 x 60 x 60 s)²  = 4 x 3.14² x ( 9380 x 10³)³ / (6.67 x 10⁻¹¹ x M)

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4 0
3 years ago
Two identical loudspeakers are driven in phase by the same amplifier. The speakers are positioned a distance of 3.2 m apart. A p
serg [7]

Answer:

f = 735 Hz

Explanation:

given,

Person distance from speakers

r₁ = 4.1 m      r₂ = 4.8 m

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d = r₂ - r₁ = 4.8 - 4.1 = 0.7 m

For destructive interference

d = \dfrac{n\lambda}{2}

where, n = 1, 3,5..

we know, λ = v/f

d = \dfrac{n v}{2f}

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4 years ago
The weight of a luggage is 69.3 N on the moon. Find its weight on the Earth.​
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Answer:

415.8N

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Given:

weight of a luggage = 69.3 N

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✓(weight on the Earth) is equivalent to 6 times weight if the moon.

✓Then, weight on the Earth) =( 69.3N × 6)

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7 0
3 years ago
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where P1 = P2 atmospheric pressure

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