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Vesna [10]
3 years ago
14

A 5.00-a current runs through a 12-gauge copper wire (diameter 2.05 mm) and through a light bulb. copper has 8.5 * 1028 free ele

ctrons per cubic meter. (a) how many electrons pass through the light bulb each second
Physics
2 answers:
Sholpan [36]3 years ago
8 0

Answer:

\frac{dN}{dt} = 3.125 \times 10^{19} electrons per second

Explanation:

As we know that electric current is defined as rate of flow of electric charge

so here we will have

i = \frac{dq}{dt}

here we know that

q = Ne

now from above equation

i = e\frac{dN}{dt}

here we know

\frac{dN}{dt} = number of electrons passing per second

e = charge of an electron

i = 5.00 Ampere

now from above equation we have

\frac{dN}{dt} = \frac{i}{e}

\frac{dN}{dt} = \frac{5}{1.6 \times 10^{-19}}

\frac{dN}{dt} = 3.125 \times 10^{19}

so above is the total number of electrons passing through wire per second

vlada-n [284]3 years ago
7 0

The correct answer is: 3.125*10^{19} electrons/second

Explanation:

5A current is passing through the copper wire and the light bulb; it means that 5 Coulombs of charge per second is passing through the wire (as current = coulombs/second). To find the electrons per second, the following formula is used:

Electrons per second = n_e=\frac{5}{e}=\frac{5}{ 1.60\cdot 10^{-19}}=3.125*10^{19}

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What is the angular displacement of the wheel between t = 5 s and t = 15 s?
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The question seems incomplete. The complete text is:

a)What is the angular displacement of the wheel between t = 5 s and t = 15 s

b)What is the angular velocity of the wheel at 15 s

And it refers to the attached figure.

a) 25 rad

The graph shown represent the angular position of the wheel at different times.

Therefore, we can simply calculate the  angular displacement between two times by calculating the difference between the angular position at t2 and the angular position at t1.

At t_1 = 5 s, the angular position from the graph is \theta_1 = 100 rad

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Therefore, the angular displacement is

\Delta \theta= \theta_2 - \theta_1 = 125-100 = 25 rad

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For a angular displacement vs time graph, the angular velocity at any time is simply equal to the slope of the curve at that time.

Here  we want to calculate the angular velocity at t = 15 s, so we have to calculate the slope at that time.

By noting that the slope is constant in the last part of the motion, we find that the slope between 10 s and 20 s is:

\frac{\Delta \theta}{\Delta t}=\frac{100 rad - 150 rad}{20 s - 10 s}=-5.0 rad/s

This slope is constant between 10 s and 20 s, so the angular velocity of the wheel at t = 15 s

\omega = -5.0 rad/s

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3 years ago
Which of the following is a force or motion that
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