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bogdanovich [222]
3 years ago
7

Two children hang by their hands from the same tree branch. the branch is straight, and grows out from the tree trunk at an angl

e of 27.5° above the horizontal. one child, with a mass of 45.6 kg, is hanging 1.28 m along the branch from the tree trunk. the other child, with a mass of 36.0 kg, is hanging 2.25 m from the tree trunk. what is the magnitude of the net torque exerted on the branch by the children
Physics
1 answer:
Ratling [72]3 years ago
7 0

The net torque exerted by the children on the branch of the tree is 1382 N-m.

The torque exert by the kids is calculated as

T= 45.6*9.8*1.28*cos27.5°+36*9.8*(2.25-1.28)cos27.5°

T=1382 N-m

Hence, The net torque exerted by the children on the branch of the tree is 1382 N-m.

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The wavelengths for visible light rays correspond to which of these options?
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Answer;

About the size of a virus or a large molecule

Explanation;

Visible light is a form of electromagnetic (EM) radiation, as are radio waves, infrared radiation, ultraviolet radiation, X-rays and microwaves. Generally, visible light is defined as the wavelengths that are visible to most human eyes.

Visible light falls in the range of the EM spectrum between infrared (IR) and ultraviolet (UV). It has frequencies of about 4 × 1014 to 8 × 1014 hertz (Hz) and wavelengths of about 740 nanometers (nm) to 380 nm .

The wavelength of visible light corresponds to the size of a virus or a large molecules which ranges from about 20 to 400 nanometres in diameter.

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3 years ago
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-In the Bohr model, as it is known today, the electron is imagined to move in a circular orbit about a stationary proton. The fo
vampirchik [111]

Answer:

4.3859007196\times 10^{-9}\ m

Explanation:

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

v = Velocity of electron = 2.4\times 10^5\ m/s

q = Charge of electron = 1.6\times 10^{-19}\ C

m = Mass of electron = 9.11\times 10^{-31}\ kg

r = Radius

The electrical and centripetal force will balance each other

\dfrac{kq^2}{r^2}=\dfrac{mv^2}{r}\\\Rightarrow r=\dfrac{kq^2}{mv^2}\\\Rightarrow r=\dfrac{8.99\times 10^9\times (1.6\times 10^{-19})^2}{9.11\times 10^{-31}\times (2.4\times 10^5)^2}\\\Rightarrow r=4.3859007196\times 10^{-9}\ m

The radius of the orbital is 4.3859007196\times 10^{-9}\ m

4 0
3 years ago
Why do telescopes give modern astronomers an advantage over people in the past
pochemuha

its because it allows modern astronomers  the ability to see farther out and more accuratly

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Which of the following rocks would most likely be found on the ocean floor
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Is there a graph or a picture
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A tennis player tosses a tennis ball straight up and then catches it after 2.07 s at the same height as the point of release.
prisoha [69]

(a) The ball will accelerate at a speed of 9.81 m/s² while it is in flight.

(b) The ball will be moving at a speed of 0 m/sec when it reaches its highest point.

(c) The ball's initial upward velocity is 20.30 m/s.

(d) It will reach a maximum height of 21.0 m.

<h3 /><h3>What is speed?</h3>

Speed is defined as the change in distance with regard to time. A scalar quantity, speed. It is a temporal element, m/sec is its unit.

The information provided in the issue is;

u is the fall's beginning speed in m/sec;

h is the fall's distance

g is the fall's acceleration or 9.81 m/sec²

a. The ball's speed while in flight is equal to the acceleration caused by gravity, which is 9.81 m/s².

b. When the ball reaches its highest point, its velocity will be zero.

c. The ball's starting velocity is;

v=u-gt

0=u-gt

u=gt

u=9.81 m/s² × 2.07 sec

u=20.30 m/s

d. The formula is used to determine the highest height it can reach.

\rm u^2 = - 2gh \\\\ (20.30)^2 = -2 \times (-9.8) \times h \\\\ 412.09  = 19.6 \times h\\\\ h = 412.09/19.6\\\\ h = 21.00 m

As a result, the ball's greatest height, beginning velocity, and acceleration are all 9.81 meters per second, zero meters per second, 20.30 meters per second, and 21 meters accordingly.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

#SPJ1

3 0
2 years ago
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