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bogdanovich [222]
3 years ago
7

Two children hang by their hands from the same tree branch. the branch is straight, and grows out from the tree trunk at an angl

e of 27.5° above the horizontal. one child, with a mass of 45.6 kg, is hanging 1.28 m along the branch from the tree trunk. the other child, with a mass of 36.0 kg, is hanging 2.25 m from the tree trunk. what is the magnitude of the net torque exerted on the branch by the children
Physics
1 answer:
Ratling [72]3 years ago
7 0

The net torque exerted by the children on the branch of the tree is 1382 N-m.

The torque exert by the kids is calculated as

T= 45.6*9.8*1.28*cos27.5°+36*9.8*(2.25-1.28)cos27.5°

T=1382 N-m

Hence, The net torque exerted by the children on the branch of the tree is 1382 N-m.

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Explanation:

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F=G\frac{m_1 m_2}{r^2}

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We know that:

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So, we can rewrite the equation in terms of G, to find its units:

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The distance between two successive troughs or crests is known as the wavelength. The wavelength of the light will be 1000 nm.

How do you define wavelength?

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

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