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bogdanovich [222]
4 years ago
7

Two children hang by their hands from the same tree branch. the branch is straight, and grows out from the tree trunk at an angl

e of 27.5° above the horizontal. one child, with a mass of 45.6 kg, is hanging 1.28 m along the branch from the tree trunk. the other child, with a mass of 36.0 kg, is hanging 2.25 m from the tree trunk. what is the magnitude of the net torque exerted on the branch by the children
Physics
1 answer:
Ratling [72]4 years ago
7 0

The net torque exerted by the children on the branch of the tree is 1382 N-m.

The torque exert by the kids is calculated as

T= 45.6*9.8*1.28*cos27.5°+36*9.8*(2.25-1.28)cos27.5°

T=1382 N-m

Hence, The net torque exerted by the children on the branch of the tree is 1382 N-m.

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Question 4 of 10 Which vector has an x-component with a length of 2?
barxatty [35]

Answer:

B

Explanation:

Look for the one with an   x coordinate of two .... answer B

4 0
2 years ago
Calculate the mass of air in a room of floor dimensions =10M×12M and height 4m(Density of air =1.26kg/m cubic​
Alinara [238K]

The volume of the room is the product of its dimensions:

10\times 12 \times 4 = 480\text{ m}^3

Now, from the equation

d=\dfrac{m}{V}

where d is the density, m is the mass and V is the volume, we deduce

m=dV

So, multiply the density and the volume to get the mass of air in the room.

7 0
4 years ago
The critical angle in air for a particular type of glass is 39.0°. What is the speed of light in this class glass? (c = 3.00 × 1
hodyreva [135]

Answer:

speed of light in glass ≈ 1.89*10^{8}m/s

Explanation:

refractive index (n) =\frac{1}{sinC}            .......................equation 1

refractive index (n) = velocity of light in air/ velocity of light in medium  ....equ2

equate equation 1 and two;

\frac{1}{sinC} = \frac{c}{speed of light in glass}

speed of light in glass = c*sinC

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speed of light in glass = 188,796,117.314 m/s

speed of light in glass ≈ 1.89*10^{8}m/s

7 0
3 years ago
) a stone is dropped from the top of a cliff. It is seen to hit the ground below after 3.55 s. How high is the cliff?
Agata [3.3K]

We use kinematic equation of motion,

S =ut+ \frac{1}{2} gt^2

Here, s is distance traveled, u is the initial velocity, t is time taken and g is acceleration due to gravity.

Given, t =3.55 s.

We take,  u = 0 because stone has no initial velocity.

Therefore,

S = 0 \times t + \frac{1}{2} \times 9.8 \ m/s^2 \times (3.55)^2 s = 61.75 \ m

Thus,  the height of cliff is approximately 61.75 m.


5 0
4 years ago
2.What is the weight of an object that has a mass of 5 kg?<br>​
Artemon [7]

Answer:

5 kg

or 11 lbs

Explanation:

4 0
3 years ago
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