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kykrilka [37]
3 years ago
12

Using the midpoint and the distance formulas, calculate he coordinate of the midpoint and the length of the segment.

Physics
1 answer:
arsen [322]3 years ago
7 0

Answer:

Explanation:

Formula to calculate the distance between two points (x_1,y_1) and (x_2,y_2) is,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Therefore, length of CD having coordinates C(3,1) and D(3, 3),

CD = \sqrt{(3-3)^2+(1-3)^2}

     = 2 units

Formula to find the midpoint of CD is,

M = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

   = (\frac{3+3}{2},\frac{1+3}{2})

   = (3, 2)

Therefore, length of CD = 2 units and (3, 2) are the coordinates of the midpoint of CD.

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A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel d
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Answer:

the distance in meters traveled by a point outside the rim is 157.1 m

Explanation:

Given;

radius of the disk, r = 50 cm = 0.5 m

angular speed of the disk, ω = 100 rpm

time of motion, t = 30 s

The distance in meters traveled by a point outside the rim is calculated as follows;

\theta = \omega t\\\\\theta = (100 \frac{rev}{\min}  \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1\min}{60 s} ) \times (30 s)\\\\\theta = 100 \pi \ rad\\\\d = \theta r\\\\d = 100\pi  \ \times \ 0.5m\\\\d = 50 \pi \ m = 157.1 \ m

Therefore, the distance in meters traveled by a point outside the rim is 157.1 m

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A car of mass 800kg travels a distance of 40m at constant speed in a duration of 2.0s. The car exerts a forward force of 15kN.
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2 years ago
A net force of 60 N north acts on an object with a mass of 30 kg. Use Newton's second law of
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Answer:

Explanation:

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If the mass goes up to say, 60, and the force stays the same, then

60 = 60a and

a = 1...if the mass goes up, the acceleration goes down.

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