Complete question:
An air-filled parallel-plate capacitor has plates of area 2.90 cm2 separated by 2.50 mm. The capacitor is connected to a(n) 18.0 V battery. Find the value of its capacitance.
Answer:
The value of its capacitance is 1.027 x 10⁻¹² F
Explanation:
Given;
area of the plate, A = 2.9 cm² = 2.9 x 10⁻⁴ m²
separation distance of the plates, d = 2.5 mm = 2.5 x 10⁻³ m
voltage of the battery, V = 18 V
The value of its capacitance is calculated as;
![C = \frac{k\epsilon_0A}{d} \\\\C = \frac{(1)(8.85\times 10^{-12})(2.9 \times 10^{-4})}{2.5 \times 10^{-3}} \\\\C = 1.027 \times 10^{-12} \ F](https://tex.z-dn.net/?f=C%20%3D%20%5Cfrac%7Bk%5Cepsilon_0A%7D%7Bd%7D%20%5C%5C%5C%5CC%20%3D%20%5Cfrac%7B%281%29%288.85%5Ctimes%2010%5E%7B-12%7D%29%282.9%20%5Ctimes%2010%5E%7B-4%7D%29%7D%7B2.5%20%5Ctimes%2010%5E%7B-3%7D%7D%20%5C%5C%5C%5CC%20%3D%201.027%20%5Ctimes%2010%5E%7B-12%7D%20%5C%20F)
Therefore, the value of its capacitance is 1.027 x 10⁻¹² F
Answer:
9 meters
Explanation:
Given:
Mass of Avi is, ![m=40\ kg](https://tex.z-dn.net/?f=m%3D40%5C%20kg)
Spring constant is, ![k=176,400\ N/m](https://tex.z-dn.net/?f=k%3D176%2C400%5C%20N%2Fm)
Compression in the spring is, ![x=20\ cm=0.20\ m](https://tex.z-dn.net/?f=x%3D20%5C%20cm%3D0.20%5C%20m)
Let the maximum height reached be 'h' m.
Now, as the spring is compressed, there is elastic potential energy stored in the spring. This elastic potential energy is transferred to Avi in the form of gravitational potential energy.
So, by law of conservation of energy, decrease in elastic potential energy is equal to increase in gravitational potential energy.
Decrease in elastic potential energy is given as:
![EPE=\frac{1}{2}kx^2\\EPE=\frac{1}{2}\times 176400\times (0.20)^2\\EPE=88200\times 0.04=3528\ J](https://tex.z-dn.net/?f=EPE%3D%5Cfrac%7B1%7D%7B2%7Dkx%5E2%5C%5CEPE%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20176400%5Ctimes%20%280.20%29%5E2%5C%5CEPE%3D88200%5Ctimes%200.04%3D3528%5C%20J)
Now, increase in gravitational potential energy is given as:
![GPE=mgh=40\times 9.8\times h=392h](https://tex.z-dn.net/?f=GPE%3Dmgh%3D40%5Ctimes%209.8%5Ctimes%20h%3D392h)
Now, increase in gravitational potential energy is equal decrease in elastic potential energy. Therefore,
![392h=3528\\\\h=\frac{3528}{392}\\\\h=9\ m](https://tex.z-dn.net/?f=392h%3D3528%5C%5C%5C%5Ch%3D%5Cfrac%7B3528%7D%7B392%7D%5C%5C%5C%5Ch%3D9%5C%20m)
Therefore, Avi will reach a maximum height of 9 meters.
Answer:
the answer to the question is a system of insulating element designed to control the path of electric current for a particular purpose
Answer:
a) I = 2279.5 N s
, b) F = 3.80 10⁵ N, c) I = 3125.5 N s and d) F = 5.21 10⁵ N
Explanation:
The impulse is equal to the variation in the amount of movement.
I =∫ F dt = Δp
I = m
- m v₀
Let's calculate the final speed using kinematics, as the cable breaks the initial speed is zero
² = V₀² - 2g y
² = 0 - 2 9.8 30.0
= √588
= 24.25 m/s
a) We calculate the impulse
I = 94 24.25 - 0
I = 2279.5 N s
b) Let's join the other expression of the impulse to calculate the average force
I = F t
F = I / t
F = 2279.5 / 6 10⁻³
F = 3.80 10⁵ N
just before the crash the passenger jumps up with v = 8 m / s, let's take the moments of interest just when the elevator arrives with a speed of 24.25m/s down and as an end point the jump up to vf = 8 m / n
c) I = m
- m v₀
I = 94 8 - 94 (-24.25)
I = 3125.5 N s
d) F = I / t
F = 3125.5 / 6 10⁻³
F = 5.21 10⁵ N
c would be the correct answer because when its a negative power your moving the decimal to the left whic makes the number smaller