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3 years ago

Using the midpoint and the distance formulas, calculate he coordinate of the midpoint and the length of the segment.

Physics

1 answer:

arsen [322]3 years ago

7 0

Answer:

Explanation:

Formula to calculate the distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Therefore, length of CD having coordinates C(3,1) and D(3, 3),

CD = $\sqrt{(3-3)^2+(1-3)^2}$

= 2 units

Formula to find the midpoint of CD is,

M = $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

= $(\frac{3+3}{2},\frac{1+3}{2})$

= (3, 2)

Therefore, length of CD = 2 units and (3, 2) are the coordinates of the midpoint of CD.

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Answer:

A) some of the rocks energy is transformed to thermal energy

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An amoeba has 1.00 x 1016 protons and a net charge of 0.300 pC. Assuming there are 1.88 x 106 fewer electrons than protons, If y

Xelga [282]

Answer:

The fraction of the protons would have no electrons $=1.88\times 10^{-10}$

Explanation:

We are given that

Amoeba has total number of protons= $1.00\times 10^{16}$

Net charge, Q=0.300pC

Electrons are fewer than protons= $1.88\times 10^6$

We have to find the fraction of protons would have no electrons.

The fraction of the protons would have no electrons

= $\frac{Fewer\;electrons}{Total\;protons}$

The fraction of the protons would have no electrons

= $\frac{1.88\times 10^{6}}{1.00\times 10^{16}}$

$=1.88\times 10^{-10}$

Hence, the fraction of the protons would have no electrons $=1.88\times 10^{-10}$

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