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dmitriy555 [2]
3 years ago
11

Point G(-3,2) is translated using the rule (x+10, y-6). What is the x-coordinate of G'? Enter your answer in the box.

Mathematics
1 answer:
aleksklad [387]3 years ago
5 0

Answer:

7 is the Anwser

Step-by-step explanation:

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What is the definition of present value?
Bezzdna [24]

Answer:

the value in the present of a sum of money, in contrast to some future value it will have when it has been invested at compound interest.

Step-by-step explanation:

6 0
3 years ago
The diameter of a small gear is 16 cm.This is 2.5 cm more than 1/4 of the diameter of a larger gear.What is the diameter of the
bagirrra123 [75]
Diameter of the larger gear  х см
1/4х = 16 - 2.5
1/4x = 13.5
x = 13.5 * 4
x = 54 cm - diameter of the larger gear / 
6 0
2 years ago
What is the measure of the central angle of a circle with radius 15 ft that intercepts a 10 ft arc?
olga2289 [7]
  • L=10ft
  • R=15ft
  • We have to find theta

\Large{\underline{\sf Solution:-}}

\\ \sf\dashrightarrow L=\dfrac{\Theta}{180}\times \pi r

\\ \sf\dashrightarrow 10=\dfrac{\Theta}{180}\times 3.14\times 15

\\ \sf\dashrightarrow 10=\dfrac{\Theta}{180}\times 47.1

\\ \sf\dashrightarrow \Theta=\dfrac{10(180)}{47.1}

\\ \sf\dashrightarrow \Theta=\dfrac{1800}{47.1}

\\ \sf\dashrightarrow \Theta=38.2°

5 0
2 years ago
Solve the equation 2.7 + x = 17
olga55 [171]
Hello!

To solve this equation, we need to isolate the variable on one side of the equation to see what it equals. 

As you can see, 2.7 is added. To get it onto the other side and cancel it from the one side, you will subtract it from both sides as shown below. Note that because of the commutative property, we can switch the places of 2.7 and x.

x+2.7-2.7=17-2.7  (Note that 2.7=2.7 is 0 in this equation.
x=14.3

Our solution is x=14.3

I hope this helped you learn how to solve equations a bit better!
4 0
3 years ago
Write a polynomial of degree 5 with zero x=0,i square root 7, -2i
professor190 [17]

Answer:

P(x)=x^5+11x^3+28x

Step-by-step explanation:

<u>Roots of a polynomial</u>

If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

P(x)=a(x-x_1)(x-x_2)(x-x_3)...(x-x_n)

Where a is an arbitrary constant.

We know three of the roots of the degree-5 polynomial are:

x_1=0;\ x_2=\sqrt{7}\boldsymbol{i}:\ x_3=-2\boldsymbol{i}

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

x_4=-\sqrt{7}\boldsymbol{i}:\ x_3=+2\boldsymbol{i}

Let's build up the polynomial, assuming a=1:

P(x)=(x-0)(x-\sqrt{7}\boldsymbol{i})(x+\sqrt{7}\boldsymbol{i})(x-2\boldsymbol{i})(x+2\boldsymbol{i})

Since:

(a+b\boldsymbol{i})\cdot (a-b\boldsymbol{i})=a^2+b^2

P(x)=(x)(x^2+7)(x^2+4)

Operating the last two factors:

P(x)=(x)(x^4+11x^2+28)

Operating, we have the required polynomial:

\boxed{P(x)=x^5+11x^3+28x}

7 0
3 years ago
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