Can someone please help me solve this?

Mathematics

1 answer:

Akimi4 [234]2 years ago

4 0

A. This is the original equation: 2x + 3 - 1 = x + 5

b. 2x + 2 = x + 5 ← combined like terms on left side
2x + 2 - 2 = x + 5 - 2 ← used inverse operation to collect constants on right side
2x = x + 3 ←simplified each side
2x - x = x - x + 3 ←used inverse operation to collect variable terms on left side
x = 3 ← simplified each side
answer x = 3

c. 2(3) + 3 - 1 = 3 + 5
6 + 3 - 1 = 8
9 - 1 = 8
8 = 8

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Suppose that 10 sophomores, 3 juniors, and 10 seniors are candidates for a prestigious mathematics award of which three will be

faltersainse [42]

Answer:

1771 possible ways

Step-by-step explanation:

In this case, we need to know first how many candidates are in total:

10 + 3 + 10 = 23 candidates in total.

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C = m! / n! (m - n)!

Where m is the total candidates and n, is the number of candidates to be chosen. Replacing this data we have:

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You mean -2x+5y=20 if it was that's how you do it
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