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Strike441 [17]
3 years ago
6

1/2 (3x + 5) = 7 anyone can someone explain this problem to me so I can understand it better.

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
3 0
The answer is x = 3

3x + 5 / 2 = 7
3x +5 = 7 x 2
3x + 5 = 14
3x = 14 - 5
3x = 9
x = 9/3
x = 3
You might be interested in
3^x= 3*2^x solve this equation​
kompoz [17]

In the equation

3^x = 3\cdot 2^x

divide both sides by 2^x to get

\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3

Take the base-3/2 logarithm of both sides:

\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}

Alternatively, you can divide both sides by 3^x:

\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13

Then take the base-2/3 logarith of both sides to get

\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}

(Both answers are equivalent)

8 0
2 years ago
Question 6<br> Express this decimal as a fraction.<br> ?<br> 1.21 =<br> ^ it has a line over the 21.
saul85 [17]

Answer: 40/33

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Determine whether each equation below does or does not represent a proportional relationship. support your answer using either a
Triss [41]

Answer:

  • As the ratio for all the points on the equation y = x is same. Hence, the equation y = x REPRESENTS a proportional relationship.
  • As the ratio for all the points on the equation y = x+2 is not same. Hence, the equation y = x + 2 DOES NOT REPRESENT a proportional relationship.

Step-by-step explanation:

                                        <u><em>Solving equation A: y = x </em></u>

Let us consider the given equation A:

                                                      y = x

  • Putting x = 1 in y = x

y = x

y = 1    ∵ x = 1

Hence, (1, 1) is the ordered pair of  y = x

  • Putting x = 2 in y = x

y = x

y = 2    ∵ x = 2

Hence, (2, 2) is the ordered pair of  y = x

  • Putting x = 3 in y = x

y = x

y = 3    ∵ x = 3

Hence, (3, 3) is the ordered pair of  y = x

  • Putting x = 4 in y = x

y = x

y = 4    ∵ x = 4

Hence, (4, 4) is the ordered pair of  y = x

  • Putting x = 5 in y = x

y = x

y = 5    ∵ x = 5

Hence, (5, 5) is the ordered pair of y = x

Lets us consider all the ordered pairs i.e. (1, 1), (2, 2), (3, 3), (4, 4) and (5, 5) to make a table for y = x.

<em>y                 x</em>

1                  1

2                 2

3                 3

4                 4

5                 5

As from the table, lets take the ratio of every point i.e. y/x

  • For (1, 1), the ratio will be y/x ⇒ 1/1 = 1
  • For (2, 2), the ratio will be y/x ⇒ 2/2 = 1
  • For (3, 3), the ratio will be y/x ⇒ 3/3 = 1
  • For (4, 4), the ratio will be y/x ⇒ 4/4 = 1
  • For (5, 5), the ratio will be y/x ⇒ 5/5 = 1

Hence, the ratio for all the points on the equation y = x is same. Hence, the equation y = x REPRESENTS a proportional relationship. Please also check the graph in attached<em> figure a.</em>

                                          <u><em>Solving equation A: y = x +2</em></u>

Let us consider the given equation A:

                                                         y = x + 2    

  • Putting x = 1 in y = x + 2

y = x + 2

y = 1 + 2 ⇒ 3  ∵ x = 1

Hence, (1, 3) is the ordered pair of y = x + 2

  • Putting x = 2 in y = x + 2

y = x + 2

y = 2 +2 ⇒ 4   ∵ x = 2

Hence, (2, 4) is the ordered pair of y = x + 2

  • Putting x = 3 in y = x + 2

y = x + 2

y = 3 + 2 ⇒ 5    ∵ x = 3

Hence, (3, 5) is the ordered pair of  y = x + 2

  • Putting x = 4 in y = x + 2  

y = x + 2  

y = 4 + 2 ⇒ 6   ∵ x = 4

Hence, (4, 6) is the ordered pair of  y = x + 2

  • Putting x = 5 in y = x + 2

y = x + 2

y = 5 +2 ⇒ 7    ∵ x = 5

Hence, (5, 7) is the ordered pair of y = x + 2

Lets us consider all the ordered pairs i.e. (1, 3), (2, 4), (3, 5), (4, 6) and (5, 7) to make a table for y = x + 2.

<em>y                 x + 2</em>

1                  3

2                 4

3                 5

4                 6

5                 7

As from the table, lets take the ratio of every point i.e. y/x

  • For (1, 3), the ratio will be y/x ⇒ 3/1 = 3
  • For (2, 4), the ratio will be y/x ⇒ 4/2 = 2
  • For (3, 5), the ratio will be y/x ⇒ 5/3 = 5/3
  • For (4, 6), the ratio will be y/x ⇒ 6/4 = 3/2
  • For (5, 7), the ratio will be y/x ⇒ 7/5 = 7/5

Hence, the ratio for all the points on the equation y = x+2 is not same. Hence, the equation y = x + 2 DOES NOT REPRESENT a proportional relationship. Please also check the graph in attached<em> figure a.</em>

<em>Keywords: equation, graph</em>

<em> Learn more equation and graphs from brainly.com/question/12767017</em>

<em> #learnwithBrainly</em>

6 0
3 years ago
SOMEONE PLEASE HELP ASAP!!!!!
Margaret [11]

Answer:

<em>x = 1</em>

<em>y = 1</em>

Step-by-step explanation:

<u>System of Equations</u>

We are given the system of equations:

2x + y = 3

x = 2y - 1

Substituting x in the first equation:

2(2y - 1) + y = 3

Operating:

4y - 2 + y = 3

5y = 3 + 2

y = 5/5 = 1

y = 1

Since:

x = 2y - 1

Then:

x = 2(1) - 1

x = 1

Solution:

x = 1

y = 1

7 0
3 years ago
What is the area of the square adjacent to the third side of the triangle?
Naddik [55]

Answer:

85 units^2 = Area of Blue Square

and

x = 5 units

Step-by-step explanation:

To do this we use the Pythagorean theorem (a^2 + b^2 = c^2). a and b represent the legs of the triangle whereas c represents the longest side of the triangle, or the hypotenuse.

Since we know the area of a square is the side length multiplied by itself (or the side length squared), \sqrt{35} is the side length of the pink square and \sqrt{50} is the side length of the green square.

That means a = \sqrt{35} and b = \sqrt{50} , so...

(\sqrt{35} )^{2} + (\sqrt{50})^{2}  = c^{2}

35 + 50 = c^2

85 = c^2

\sqrt{85} = c

Now we need to square the square root of 85 to find the area of the blue square.

(\sqrt{85})^{2}  = Area of blue square

85 units^2 = Area of Blue Square

To solve the other question we use the same formula again.

x^2 + 12^2 = 13^2\\x^2 +144 = 169\\-144\\x^2 =  25\\x=\sqrt{25} \\x=5

x = 5 units

3 0
3 years ago
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