Given expressions;
f(x) = x² + 6x + 7
g(x) = 8x² - 2
h(x) = 3x + 4
k(x) = x - 3
Find f(2) - g(2). k(2)
f(2) = 2² + 6(2) + 7 = 23
g(2) = 8(2)² - 2 = 30
k(2) = 2 - 3 = -1
Now, f(2) - g(2). k(2) = 23 - (30)(-1)
= 53
The solution to the problem is 53
Answer:
C
Step-by-step explanation:
The expression is x>55 and 55 isn't included
Answer:
Variable
Step-by-step explanation:
If you can substitute a unknown variable with another expression that is equal, you can then solve for another variable, and with that equal expression, solve for the first variable.
Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
