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Masja [62]
3 years ago
11

Nal parts. The Which statements about the clock are accurate? Check

Mathematics
2 answers:
bearhunter [10]3 years ago
8 0

Answer:

1 - 3 - 5

Step-by-step explanation:

i took in the page

KATRIN_1 [288]3 years ago
6 0

Answer:

The central angle measure when one hand points

at 2 and the other points at 4 is 60°

The circumference of the clock is about 19 in.

With one hand at 5 and the other at 10, the minor

arc formed by the hands is about 15.7 in.The minor arc measure when one hand points at 1

and the other hand points at 9 is 150° The length of the minor arc between 11 and 2 is the

same as the length of the minor arc between 7 and

10.

Step-by-step explanation:just learned it

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Solve and simplify, typing the final answer as a fraction 1/4 ÷ 3/8
natita [175]

[ Answer ]

2 / 3


[ Explanation ]


1 * 8 / 4 * 3


8 / 12


Simplify:

2 / 3


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6 0
3 years ago
Read 2 more answers
How to get a perimeter of 200
Gnom [1K]

Answer:

You could have a square with side of 50 ft.

Step-by-step explanation:

4 0
3 years ago
if a person paid rs 32 as VAT to buy an article of cost Rs 2750 then how much money he /she pay? find it​
bekas [8.4K]

The total amount paid for the article is Rs2782

<h3>How to determine the amount paid?</h3>

The given parameters are:

Article = Rs 2750

VAT = Rs 32

The amount paid is calculated using:

Amount = Article + VAT

This gives

Amount = 2750 + 32

Evaluate

Amount = 2782

Hence, the total amount paid for the article is Rs2782

Read more about VAT at:

brainly.com/question/20392481

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7 0
2 years ago
Prove that sinA-sin3A+sin5A-sin7A/cosA-cos3A-cos5A+cos7A= cot2A
MAVERICK [17]
Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.

We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)

N = -(sin7A - sinA) + sin5A - sin3A
    = -2cos4A*sin3A + 2cos4A*sinA
    = 2cos4A(sinA - sin3A)
    = 2cos4A*2cos(2A)sin(-A)
    = -4cos4A*cos2A*sinA

D = cos7A + cosA - (cos5A + cos3A)
   = 2cos4A*cos3A - 2cos4A*cosA
   = 2cos4A(cos3A - cosA)
   = 2cos4A*(-2)sin2A*sinA
   = -4cos4A*sin2A*sinA

Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
       = cos2A/sin2A
      = cot2A

This verifies the identity.
4 0
3 years ago
1. Write a linear equation with the given information
Readme [11.4K]

1) The equation of the parallel line in Slope Intercept Form is; y = -x - 1

2) The equation of the perpendicular line in Slope Intercept Form is;

y = ³/₂x - 4

<h3>How to write equation in Slope Intercept Form?</h3>

1) When two lines are parallel, it means their slopes are the same.

Formula for equation in slope intercept form is;

y = mx + c

where;

m is slope

c is y-intercept

Thus, slope of y = -x + 1 is m = -1.

Equation of parallel line is;

(y - (-5))/(x - 4) = -1

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y = -x - 1

2) When two lines are perpendicular, it means their slopes are the negative inverse of each other. Thus;

Slope of line = -2/3 and so slope of perpendicular line = 3/2. Thus, equation of new line is;

(y + 1)/(x - 2) = 3/2

2y + 2 = 3x - 6

2y = 3x - 8

y = ³/₂x - 4

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3 0
2 years ago
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