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2 years ago

Another way to express 52+24

1 answer:

4 0

We know that: 52 + 24 = 76.
You can also express it this way:
52 + 24 = 50 + 2 + 20 + 4 = ( 50 + 20 ) + ( 2 + 4 ) = 70 + 6 = 76
Or ( since 4 * 13 = 52 and 4 * 6 = 24 ):
52 + 24 = 4 * 13 + 4 * 6 = 4 * ( 13 + 6 ) = 4 * 19 = 76.

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The area of a rectangular horse pasture is 268,500 square yards. The length of the pasture is 5 yards less than three times the

Setler79 [48]

Answer: width = 300

<u>Step-by-step explanation:</u>

Area (A) = Length (L) x width (w)

Given: A = 268,500

L = 3w - 5

w = w

268,500 = (3w - 5) x (w)

268,500 = 3w² - 5w

0 = 3w² - 5w - 268,500

0 = (3w + 895) (w - 300)

0 = 3w + 895 0 = w - 300

-985/3 = w 300 = w

Since width cannot be negative, disregard w = -985/3

So the only valid answer is: w = 300

8 0

3 years ago

A new vehicle is worth $2500. If it depreciates records in value 12% per year, after 6 years what will it be worth

Margaret [11]

Answer:

Step-by-step explanation:

2500 - 12%

12% of 2500 = 300

2500 - 300 = 2200

12% of 2200 = 264

2200-264=1936

Repeat another 4 times

8 0

3 years ago

Find c. Round to the nearest tenth

sergeinik [125]

Answer:

c = <u>0.5 cm</u>

Step-by-step explanation:

Using the Sine rule in the triangle, then

= ( cross- multiply )

c × sin105° = 2 × sin15° ( divide both sides by sin105°

c = ≈ 0.5 cm ( to the nearest tenth )

8 0

2 years ago

(Photo attached) Trig question. I partially understand it, but not completely. Please explain! :) Thanks in advance.

aliya0001 [1]

Answer:

A = 2
B = 3

Step-by-step explanation:

You can start by recognizing 19/12π = π +7/12π, so the desired sine is ...

sin(19/12π) = -sin(7/12π) = -(sin(3/12π +4/12π)) = -sin(π/4 +π/3)

-sin(π/4 +π/3) = -sin(π/4)cos(π/3) -cos(π/4)sin(π/3)

Of course, you know that ...

sin(π/4) = cos(π/4) = (√2)/2

cos(π/3) = 1/2

sin(π/3) = (√3)/2

So, the desired value is ...

sin(19π/12) = -(√2)/2×1/2 -(√2)/2×(√3/2) = -(√2)/4×(1 +√3)

Comparing this form to the desired answer form, we see ...

A = 2

B = 3

5 0

2 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.

Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

AD+DB=3

x+DB = 3

DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

$BC^{2} = DB^{2} +CD^{2}$

$BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}$

$BC^{2} =(3-x)^{2} +2$

Since given AD=BC,let us plugin BC=x in above step.

$x^{2} =(3-x)^{2} +2$

$x^{2} =9-6x+x^{2} +2$

6x=11

x= $\frac{11}{6}$

Now we know AD=x= $\frac{11}{6}$ and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

$AC^{2} =AD^{2} +DC^{2}$

$AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}$

$AC^{2} =\frac{193}{36}$

$AC=\sqrt{\frac{193}{36} }$ = 2.315cm

3 0

3 years ago