Another way to express 52+24

PLS ANSWER FAST solve for the unknown... 3^x = 9^x+5

irinina [24]

I think it’s -1 x
3 minus the nine equals -6x and -6x divides by 5 equals -1

7 0

3 years ago

Jules César est né en -100.Il est mort en -44.A quel âge est il mort?

lorasvet [3.4K]

Jules César avait 56 ans

100 av. J.-C. - 44 av. J.-C.

#ApprendreAvecBrainly

brainly.com/question/21842076

4 0

3 years ago

A) 0.15 B) an equal sign C) a multiplication sign D) a percent sign

nekit [7.7K]

Answer:

B

Step-by-step explanation:

What is 15% of 60 is nothing but What equals 15% of 60 or What = 15% of 60

8 0

3 years ago

A soccer ball manufacturer wants to estimate the mean circumference of soccer balls within 0.1 in. Determine the minimum sample

leva [86]

Answer:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (2)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got $z_{\alpha/2}=1.96$ , replacing into formula (2) we got:

$n=(\frac{1.96(0.25)}{0.1})^2 =24.01$

So the answer for this case would be n=25 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=0.25$ represent the population standard deviation

n represent the sample size (variable of interest)

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

And on this case we have that ME =0.1 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (2)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got $z_{\alpha/2}=1.96$ , replacing into formula (2) we got:

$n=(\frac{1.96(0.25)}{0.1})^2 =24.01$

So the answer for this case would be n=25 rounded up to the nearest integer

8 0

4 years ago

2.2.2.2.2.2.2exponential form

Allisa [31]

2^7

(2 to the 7th power)

3 0

4 years ago