Can someone please help me.

I need help with question 16

Contact [7]

The answers to the questions are C=11 and D=3

5 0

3 years ago

Triangle A is reflected in the x-axis to give B.

nikitadnepr [17]

Answer:

The answer is below

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation is rotation, reflection, translation and dilation.

If a point A(x, y) is reflected over the x axis, the new point is at A'(x, -y). If a point B(x, y) is reflected over the y axis, the new point is at A'(-x, y).

Triangle A has vertex at (-4, -2), (-4, -5) and (-2, -5). If triangle A is reflected in the x axis to give triangle B, the vertex of triangle B is (-4, 2), (-4, 5) and (-2, 5).

If triangle B is reflected in the y axis to give triangle C, the vertex of triangle C is at (4, 2), (4, 5) and (2, 5). Hence the transformation is:

(x, y) ⇒ (-x, -y)

8 0

3 years ago

If n = 10 and p = 0.70, then the standard deviation of the binomial distribution is

Leya [2.2K]

For a binomial distribution, the variance is
$\sigma^2=npq=np(1-p)=10*0.7*0.3=2.1$
$\sigma=standard\,deviation=\sqrt{2.1}=1.449$ (to 3 decimal places)

6 0

3 years ago

Please help!!!!!!!!!

uranmaximum [27]

Is there any choices because i got 2 solutions

8 0

3 years ago

Some research suggests that police officers are more likely to make an arrest in the presence of bystanders. If mentally disorde

zmey [24]

Answer:

$t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638$

$p_v =P(t_{(19)}>1.638)=0.0589$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=7.03$ represent the sample mean

$s=9.42$ represent the sample standard deviation

$n=20$ sample size

$\mu_o =3.58$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 3.58 :

Null hypothesis: $\mu \leq 3.58$

Alternative hypothesis: $\mu > 3.58$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638$

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since is a right tailed test the p value would be:

$p_v =P(t_{(19)}>1.638)=0.0589$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.

7 0

3 years ago