Which operation should be performed last in this problem: 3^2 + 7 × 4? Why?
2 answers:
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E = amount she put for Education
CD = amount she put for a Certificate of Deposit.
so, whatever those amounts are, we know that all she got is 70,000 bucks total, so E + CD = 70000.
how much is three times the CD? well, 3*CD or 3CD.
how much is 10,000 more than that? well 3CD + 10000.
since we know that the amount on Education was 10000 more than three times the CD, then E = 3CD + 10000.
how much was it invested in the CD? well, CD = 70000 - E.
CD = amount she put for a Certificate of Deposit.
so, whatever those amounts are, we know that all she got is 70,000 bucks total, so E + CD = 70000.
how much is three times the CD? well, 3*CD or 3CD.
how much is 10,000 more than that? well 3CD + 10000.
since we know that the amount on Education was 10000 more than three times the CD, then E = 3CD + 10000.
how much was it invested in the CD? well, CD = 70000 - E.
I'm more visual, but if you're not, and this confuses you, ask me, and I'll explain it.
