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Gelneren [198K]
3 years ago
10

Match each step of the proof with the justification for the step.

Mathematics
1 answer:
12345 [234]3 years ago
4 0

Answer:

uh

Step-by-step explanation:

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The area of a rectangle is 24 square cm. the length of the rectangle is 8 cm. find the perimeter
telo118 [61]
The perimeter is 22 cm

6 0
3 years ago
Graph the line y = 3x
ollegr [7]

Answer:

literally google graphing calculator and type 3x

7 0
2 years ago
Read 2 more answers
Creating an Exponential Model
belka [17]

Answer:

P = $300

r = 0.15

n = 12

$544.61  (to the nearest cent)

P(1+r)^t

$524.70  (to the nearest cent)

Step-by-step explanation:

P = principal amount = $300

r = annual interest rate in decimal form = 15% = 15/100 = 0.15

n = number of times interest is compounded per unit t = 12

<u>How much she'll owe in 4 years</u>

P = 300

r = 0.15

n = 12

t = 4

P(1+\frac{r}{n})^{nt}=300(1+\frac{0.15}{12})^{12 \times 4}

= $544.61  (to the nearest cent)

<u>Yearly compounding interest rate</u>

P(1+r)^t

<u>How much she'll owe in 4 years at yearly compounding interest</u>

P(1+r)^t=300(1+0.15)^4

= $524.70  (to the nearest cent)

7 0
3 years ago
WILL MARK BRAINLIST!!
sergiy2304 [10]

Answer:

66 in.

Step-by-step explanation:

the rectangle has an area of 48in. because 4x11 = 48. The triangles have a base of 6 because 12 ÷ 2=6. the formula for area of a triangle is BxHx1/2 and the height is 3in so 6x3= 18 and 18x1/2=9 and there is two triangles and the other has the same area. Then you add up the area of everything so 48+9+9 = 66

3 0
3 years ago
I just need 30 please
PIT_PIT [208]

In the smaller triangle, let y be the length of the smallest leg. Then the smallest leg in the larger triangle is 14-y.

Within the scope of the smaller triangle, we have y such that

x^2+y^2=13^2\implies y=\sqrt{13^2-x^2}

Then within the larger the triangle, we would have

x^2+(14-y)^2=15^2\iff x^2+\left(14-\sqrt{13^2-x^2}\right)^2=15^2

Now we can solve for x:

x^2+14^2-28\sqrt{13^2-x^2}+(13^2-x^2)=15^2

\implies x=12

8 0
3 years ago
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