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OverLord2011 [107]
3 years ago
14

tres hermanos danvueltas circuito en bicicleta. el mayor tarda 18 en dar Una vuelta el del medio 24 minutos yel menos 36 minutos

si partieron al mismo tiempo ¿despues de cuanto se vuelven a encontrar y cuantas vueltas da cada uno?
Mathematics
1 answer:
hodyreva [135]3 years ago
6 0
Tienes que hallar el mínimo común múltiplo de las 3 cantidades.

18= 2×3²
24= 2³×3
36= 2²×3²

mcm(18,24,36) = 2³×3²=8×9= 72

Eso quier decir que si partieron a la misma hora se encontraran  de nuevo en el punto de partida 72 minutos después de la salida.

Las vueltas que habrán realizado será el resultado de dividir 72 entre el tiempo que tardan en dar una vuelta

<span>Mayor: </span>  = 4

<span>Mediano: </span>  = 3

<span>Pequeño: </span>  =  2

Soluciónes:

se vuelven a encontrar a los 72 min de la salida
<span>El mayor dió 4 vueltas, el mediano 3 y el pequeño 2</span>
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