Right angles are always 90 degrees. The answer is C.
Hope this helps.
The point B has coordinates (-4,2) and C has coordinates (-2,-2). We are going to calculate the slope of the line

Then, we are going to calculate the intercept using the slope m=-2 and the point (-4,2).
y=mx+b
2 = -2*(-4)+b
Isolating b we get
2-8=b= -6
The equation would be
y=-2x-6, option A
The end point for a 192 degree angle is located in the third quadrant, where both x and y are negative, so both sin192, cos192 are negative.
It’s in Quadrant I. Because it’s not on the origin and it doesn’t fall on any of the axis