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4 years ago

Help me please ASAP

Mathematics

1 answer:

alekssr [168]4 years ago

6 0

4^15
answer is D

hope it helps....

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The mean of a sequence of n numbers is m. If we split the sequence into two sequences of lengths n1 and n2 and compute their mea

Furkat [3]

The mean of a sequence of numbers is the average.

The true statement is: $\mathbf{mn = m_1 \times n_1 + m_2 \times n_2}$

The given parameters are:

$\mathbf{Mean = m}$

$\mathbf{Size = n}$

The mean of a dataset is calculated as:

$\mathbf{Mean = \frac{\sum x}{Size}}$

So, we have:

$\mathbf{m = \frac{\sum x}{n}}$

Multiply both sides by m

$\mathbf{\sum x = mn}$

When the sequence is split into two, we have:

$\mathbf{\sum x_1 = m_1\times n_1}$

$\mathbf{\sum x_2 = m_2\times n_2}$

Where:

$\mathbf{\sum x_ = \sum x_1 + \sum x_2}$

So, we have:

$\mathbf{mn = m_1 \times n_1 + m_2 \times n_2}$

Hence, the true statement is: $\mathbf{mn = m_1 \times n_1 + m_2 \times n_2}$

Read more about mean and averages at:

brainly.com/question/16217700

8 0

3 years ago

Which of the following expressions is equal to 5 to the 6th power divided by 5 to the 5th power

Jobisdone [24]

Asey

remember
$\frac{x^m}{x^n}=x^{m-n}$
so

$\frac{5^6}{5^5}=5^{6-5}=5^1=5$

8 0

3 years ago

Read 2 more answers

Find the odds for and the odds against the event rolling a fair die and getting a 1, a 4,or a 5

slega [8]

Answer:

Odds for = Odds against = 1/2

Step-by-step explanation:

In a fair die, we have {1, 2, 3, 4, 5, 6} and $n(S) = 6$

{1, 4, 5} and {2, 3, 6} constitute the entire sample space.

So, Probability of getting a 1 or a 4 or a 5

= Probability of getting a 1 +

Probability of getting a 4 +

Probability of getting a 5

= $\frac{1}{6} + \frac{1}{6} + \frac{1}{6}$

= $\frac{3}{6} = \frac{1}{2}$

Therefore, Odds for 1 or 4 or 5 = $\frac{1}{2}$ .

Since, Probability of getting a number between 1 and 6 is 1 and Probability of getting a number from 2 or 3 or 6 = $\frac{1}{2}$ , we have:

Probability of not getting a 1 or 4 or 5 = 1 - $\frac{1}{2}$

= $\frac{1}{2}$

Hence, odds for and odds against = $\frac{1}{2}$

8 0

3 years ago

Please I need help I have no idea how to do this and it’s due soon!

Anon25 [30]

I do this but I don’t remember how

8 0

4 years ago

A rocket is launched from a tower. The height of the rocket, y in feet is related to the time after launch, x in seconds, by the

gizmo_the_mogwai [7]

Step-by-step explanation:

The height of the rocket y in feet is related to the time after launch, x in seconds, by the given equation i.e.

$y=-16x^2+165x+78$ ......(1)

It is required to find the maximum height reached by the rocket. For maximum height put $\dfrac{dy}{dx}=0$ .

So,

$\dfrac{d(-16x^2+165x+78)}{dx}=0\\\\-32x+165=0\\\\32x=165\\\\x=5.15\ s$

Put x = 5.15 in equation (1).

$y=-16(5.15)^2+165(5.15)+78\\\\y=503.39\ m$

So, the maximum height reached by the rocket is 503.39 m.

5 0

4 years ago