use a mortar & pestle to grind the solute into smaller particles, thus increasing the surface area.
Answer:
1. relative time
2.absolute time
Explanation:
Time that is measured in definite periods such as minutes, days, and years is called
a. Relative time.
b. absolute time.
Answer:
At equilibrium, reactants predominate.
Explanation:
For every reaction, the equilibrium constant is defined as the ratio between the concentration of products and reactants. Thus, for the reaction N2 (g) + O2 (g) ⇌ 2NO the expression of its equilibrium constant is:
![Keq = \frac{[NO]^{2}}{[O_{2} ][N_{2}]}](https://tex.z-dn.net/?f=Keq%20%3D%20%5Cfrac%7B%5BNO%5D%5E%7B2%7D%7D%7B%5BO_%7B2%7D%20%5D%5BN_%7B2%7D%5D%7D)
Since the equilibrium constant is Keq = 4.20x10-31 the concentration of reactants O2 and N2 must be much higher than products to obtain such a small number as 4.20x10-31 at the equilibrium. Hence, at equilibrium reactants predominate.
Answer:
All of the statements above are true.
Explanation:
Ice is solid water. Ice consists of an array of water molecules arranged into a crystal lattice. Ice has spaces between the water molecules so it is less dense than liquid water. Ice is about 9% less dense than liquid water. This accounts for the fact that it floats on water.
Ice contains more hydrogen bonds per water molecule when compared to liquid water.
The choices that should have accompanied this question were:
A. 1
<span>B. 2 </span>
<span>C. 3 </span>
<span>D. 4
</span>
My answer is B. 2.
Below is an explanation, I found while doing the research.
<span>Phosphate needs 3 electrons each totaling 6 electrons so each zinc will need to give up 2 electrons.
Phosphate wants to imitate the electron configuration of Argon because noble configurations are the most stable. With P getting the extra electrons the valence shell will be 3s2 3p6, which is the same as Argon. Without the extra electrons, the P valence shell looks like this 3s2 3p3, now you can see why each phosphorus wants 3 more electrons, that will make it 3s2 3p6, just like Argon.</span>
