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faust18 [17]
4 years ago
9

What does biodiversity indicate about an ecosystem

Chemistry
1 answer:
lawyer [7]4 years ago
6 0
It indicates that the ecosystem is functional with different species



bi·o·di·ver·si·ty[ˌbīōdiˈvərsədē, ˌbīōˌdīˈvərsədē]nounthe variety of life in the world or in a particular habitat or ecosystem.

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If the density of a certain alcohol is 0.785 g/mL, what volume of the alcohol would have a mass of 75.0 g
Gemiola [76]

Answer:

95.54mL

Explanation:

To calculate the volume that would have that mass, what is needed to be done is to use the formula that relates mass, density and volume.

Mathematically,

mass = density * Volume

But in this particular question we are to calculate the volume, we already have the mass and the density.

Rearranging the equation gives the following:

volume = mass/density

Our mass here is 75.0g while our density is 0.785g/mL

Hence, volume = 75/0.785 = 95.54mL

4 0
4 years ago
Read 2 more answers
Why don't the particles in a solid move past one another?
zlopas [31]

Answer:

the attractive forces keep the particles together tightly enough so that the particles do not move past each other.

Explanation:

In the solid the particles vibrate in place.

7 0
3 years ago
If the density of chloroform is 1.5 g/cm³, what is the mass of 50.0 cm³ of chloroform?
Marianna [84]
Density = mass / volume

1.5 = m / 50.0

m = 1.5 x 50.0

m = 75 g

hope this helps!
6 0
4 years ago
Read 2 more answers
Write a question about something else you would like to learn about extremophiles.
ivanzaharov [21]
I would probally say,

Can ants survive a plane ride?
8 0
4 years ago
g How many grams of beryllium are needed to produce "11.5" g of hydrogen gas?Be(s) + 2H 2 O(l) → Be(OH) 2 (aq) + H 2 (g)
slega [8]

Answer:

m_{Be}=51.3gBe

Explanation:

Hello,

In this case, with the given chemical reaction:

Be(s) + 2H_2 O(l) \rightarrow Be(OH)_ 2 (aq) + H _2 (g)

We can notice a 1:1 mole ratio between hydrogen gas and beryllium metal, therefore, beryllium requirement is computed as shown below:

m_{Be}=11.5gH_2*\frac{1molH_2}{2.02gH_2} *\frac{1molBe}{1molH_2} *\frac{9.01gBe}{1molBe}\\ \\m_{Be}=51.3gBe

Regards.

6 0
4 years ago
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