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const2013 [10]
3 years ago
13

Tony thinks the unknown is KI while Steve thinks the unknown is LiCL. Who is correct? Support your choice with evidence/reaction

s.

Chemistry
1 answer:
qaws [65]3 years ago
4 0

Answer:

um I'm not sure go ask your grandma

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Three radioisotopes are being discussed in a chemistry class. Technetium-99m has a half-life of 6 hours. Rubidium-87 has a half-
suter [353]
B.)<span>A doctor would use technetium-99m because a short half-life indicates a quick measurement, and a geologist would use rubidium-87 because a longer half-life means that there is a longer time to measure old rock. </span>
3 0
3 years ago
Read 2 more answers
An atom has 24 protons and 23 electrons and 28 neutrons what charge does this atom have?
alina1380 [7]

Answer:

1+

Explanation:

the number of protons tells you which element it is in the periodic table, you can notice that there is 1 less electron that then there is protons which means that the element had to give 1 electron away. When you get rid of 1 e- you have 1 proton more that electrons so that's why it's 1+

also the element is Cr

3 0
3 years ago
A force of 99 N causes a box to accelerate at a rate of 11 m/s2. What is the mass of the box? (Ignore frictional effects.)
wlad13 [49]
F =  ma

<span>m = F/a = 99/11 = 9 kg</span>
3 0
3 years ago
Read 2 more answers
The sulfur content of an ore is determined gravimetrically by reacting the ore with concentrated nitric acid and potassium chlor
katen-ka-za [31]

Answer:

13.92 %

Explanation:

Mass of BaSO_4 = 12.5221 g

Molar mass of BaSO_4 = 233.43 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{12.5221\ g}{233.43\ g/mol}

Moles of BaSO_4 = 0.0536 moles

According to the given reaction,

Ba^{2+}_{(aq)}+SO_4^{2-}_{(aq)}\rightarrow BaSO_4_{(s)}

1 mole of BaSO_4 is formed from 1 mole of SO_4^{2-}

Thus,

0.0536 moles of BaSO_4 is formed from 0.0536 moles of SO_4^{2-}

Moles of SO_4^{2-} = 0.0536 moles

Moles of sulfur in 1 mole SO_4^{2-} = 1 mole

Moles of sulfur in 0.0536 mole SO_4^{2-} = 0.0536 mole

Molar mass of sulfur = 32.065 g/mol

Mass = Moles * Molar mass = 0.0536 * 32.065 g = 1.7187 g

Mass of ore = 12.3430 g

Mass % = \frac{Mass\ of\ Sulfur}{Mass_{ore}}\times 100 = \frac{1.7187}{12.3430}\times 100 = 13.92 %

3 0
4 years ago
N2(g) + 2H(g) -&gt; N2 H4(g) What are the volumes of N2 gas and H2 gas required to form 28.5 grams of N2 H4 at 30'C and 1.50 atm
FromTheMoon [43]

Answer:

Volume of N₂ = 14.76 L

Volume of H₂ = 29.52 L

Explanation:

Given data:

Mass of N₂H₄ formed = 28.5 g

Pressure = 1.50 atm

Temperature = 30°C (30+273 = 303 k)

Volume of N₂ and H₂ needed = ?

Solution:

Chemical equation:

N₂ + 2H₂  →  N₂H₄

Number of moles of N₂H₄ formed = mass/ molar mass

Number of moles of N₂H₄ formed = 28.5 g/ 32 g/mol

Number of moles of N₂H₄ formed = 0.89 mol

Now we will compare the moles of N₂H₄ with N₂ and H₂ form balance chemical equation.

                N₂H₄                :                 N₂

                   1                     :                   1

                  0.89               :               0.89

                N₂H₄                :                 H₂

                   1                    :                  2

                 0.89               :                2×0.89 = 1.78 mol

Volume of H₂:

PV = nRT

1.50 atm × V = 1.78 mol × 0.0821 atm.L/mol.K × 303 K

V = 44.28atm.L /1.50 atm

V = 29.52 L

Volume of N₂:

PV = nRT

1.50 atm × V = 0.89 mol × 0.0821 atm.L/mol.K × 303 K

V = 22.14 atm.L /1.50 atm

V = 14.76 L

6 0
3 years ago
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