The classical bonding model which best explains the bonding in the compound NaH₂PO₄ is Hydrogen bonding.
<h3>What is Classical bonding model ?</h3>
By classical, we mean models that do not take into account the quantum behavior of small particles, notably the electron.
These models generally assume that electrons and ions behave as point charges which attract and repel according to the laws of electrostatics.
Sodium dihydrogen phosphate (NaH₂PO₄) is monoclinic, In which, the four independent hydrogen atoms were located on a difference map; they are involved in four O … O Hydrogen-bonds of length 2.654 (2), 2.589 (2), 2.559 (2), and 2.500 (2) Å.
The short contact (2.500 Å), which is not astride any symmetry element, is of the type O-H … O (asymmetrical).
The distorted coordination polyhedra of the sodium atoms are discussed in the light of recent theories on electrostatic balance.
Hence, the classical bonding model which best explains the bonding in the compound NaH₂PO₄ is Hydrogen bonding.
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Answer:
Only BF₃ is non polar.
Explanation:
The non polar molecule is one which will have zero dipole moment.
This zero dipole moment is possble if
a) the bonds are non polar (completely) and there is no lone electrons
b) the bonds are polar but the overall dipole moment cancel each other due to planar geometry of molecule
i) BF₃ : This is trigonal planar molecule. The overall dipole moment is zero due to symmetric distribution of electrons and thus dipole cancel each other.
ii) NF₃ : there is lone pair of electron and the bonds are polar.
iii) PBr₃: Again presence of lone pair of electrons and thus ssymmetric distribution of electrons
iv) BrCl₃ : The bonds are polar and molecule is not planar.
v) IF₃ : bonds are polar.
The amount of absorption force is not same at all time and at all where .
It has difference at different time periods
So during those the curve goes up and down and repeat this flow
So there are dips
D = m / V
3.26 = m / 0.313
m = 3.26 x 0.313
m = 1.02038 g
hope this helps!