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Sonbull [250]
4 years ago
11

An acute triangle has side lengths 21 cm, X cm, and 2x cm. If 21 is one of the shorter side of the triangle, what is the greates

t possible length of the longest side, rounded to the nearest 10th?
Mathematics
2 answers:
tia_tia [17]4 years ago
4 0
The triangle inequality tells us that the sum of the two shorter sides of a triangle must be greater than the third side.

Here, 21 cm is one of the shorter sides, and x cm must be the length of the other shorter side.

So using the triangle inequality, 
21+x > 2x
or x<21 cm
To the nearest 0.1 cm, the greatest possible length of the longest side (2x) is 2*21-0.1 cm = 41.9 cm < 2x=42 cm.

IrinaVladis [17]4 years ago
4 0

Answer: 42

Step-by-step explanation:

C

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If 12 is replaced with 3 in the following set what will happen with the value of the range 28,45,12,34,36,45,19,20
nordsb [41]

Answer:

The interquartile range remains the same.

Step-by-step explanation:

Interquartile range is the difference between first and third quartile.

I.Q.R.=Q_3-Q_1

The given data is

28, 45, 12, 34, 36, 45, 19, 20

Arrange the data is ascending order.

12, 19, 20, 28, 34, 36, 45, 45

(12, 19, 20, 28), (34, 36, 45, 45)

(12, 19), (20, 28), (34, 36), (45, 45)

The first quartile is midpoint of 19 and 20 and the third quartile is the midpoint of 36 and 45.

Q_1=\frac{19+20}{2}=19.5

Q_3=\frac{36+45}{2}=40.5

I.Q.R.=Q_3-Q_1

I.Q.R.=40.5-19.5=21

The interquartile range of given data is 21.

If 12 is replaced with 3 in the following set, then the given data is

3, 19, 20, 28, 34, 36, 45, 45

(3, 19, 20, 28), (34, 36, 45, 45)

(3, 19), (20, 28), (34, 36), (45, 45)

The first quartile is midpoint of 19 and 20 and the third quartile is the midpoint of 36 and 45.

Q_1=\frac{19+20}{2}=19.5

Q_3=\frac{36+45}{2}=40.5

I.Q.R.=Q_3-Q_1

I.Q.R.=40.5-19.5=21

The interquartile range of given data is 21.

The interquartile range remains the same. Therfore option 3 is correct

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Answer:

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